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lilavasa [31]
3 years ago
7

Determine the chemical formula for the compound, diaquadicarbonylzinc tetrabromopalladate(iv).

Chemistry
2 answers:
kati45 [8]3 years ago
6 0
Missing question:
<span>A. [PdZn(H2O)2(CO)2]Br4. 
B. [Zn(H2O)2(CO)2]2[PdBr4]. 
C. [Pd(H2O)2][Zn(CO)2]Br4. 
D. [Pd(H2O)2]2[Zn(CO)2]3Br4. 
E. [Zn(H2O)2(CO)2][PdBr4].
</span>Answer is: E. [Zn(H2O)2(CO)2][PdBr4]..
In this complex diaqua means two waters (H₂O), <span>dicarbonyl means two carbonyl groups (CO), zinc(Zn) and palladium (Pd) are central atoms or metals, bromine has negative charge -1. Bromine, water and carbonyl are ligands.</span>
olga nikolaevna [1]3 years ago
5 0

Answer:

[Zn(H_2O)_2(CO)_2][PdBr_4]

Explanation:

Hello,

In this case, one could build-up the formula, via analyzing the name as follows:

- It says tetrabromopalladate (IV), it means that it is a mixed anion, composed by four bromine atoms (tetrabromo) and one palladium atom due suffix ate), therefore the anion is [PdBr_4].

- By means of the cation, it starts by diaqua, so it has two H_2O as an aquocation. Next, is says dicarbonyl, so two carbonyl groups C=O are bonded as well. Finally, the metallic part is given by the presence of zinc, so the cation turns out as [Zn(H_2O)_2(CO)_2] by complexity.

Therefore, the resulting formula is: [Zn(H_2O)_2(CO)_2][PdBr_4]

Best regards.

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