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slavikrds [6]
3 years ago
8

What are the 3 types of zeros?

Chemistry
1 answer:
kotegsom [21]3 years ago
8 0
Leading zeros
Captive zeros
Trailing zeros
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What is the hybridization of sb in the molecule sbcl52–? antimony (sb) can accept up to twelve electrons?
Setler79 [48]

The valence electron configuration for antimony (Sb) is:

Sb = 5s²5p³5d⁰

In SbCl₅²⁻, antimony has a -2 charge i.e. it has 2 additional electrons

Sb²⁻ = 5s²5p⁵5d⁰

Following a two electron transition from p→d orbital we have:

Sb²⁻ = 5s²5p³5d²

There is a total of 5 unpaired electrons (3 in the p and 2 in the d) which can form five bonds with the 5 Cl atoms.

Thus the hybridisation of Sb in SbCl₅²⁻ is sp³d²


5 0
3 years ago
Read 2 more answers
Calculate the amount in moles of 125 g of CaSO4.
Leto [7]

Answer:

Number of moles = 0.92 mol

Explanation:

Given data:

Mass of CaSO₄ = 125 g

Number of moles of CaSO₄ = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of CaSO₄:

Molar mass of CaSO₄ = 40 + 32+ 16×4

Molar mass of CaSO₄ = 40 + 32+ 64

Molar mass of CaSO₄ = 136 g/mol

Number of moles:

Number of moles = mass/ molar mass

Number of moles = 125 g/ 136 g/mol

Number of moles = 0.92 mol

7 0
3 years ago
You pimp air into your volleyball the ball mass is?
Mumz [18]

Answer: When it comes to maintaining your volleyball ball, there are some things you should get accustomed to doing. One of the most important is knowing how to inflate it. The professionals keep the psi of a ball at 0.3 to 0.325 for indoor balls and at 0.175 to 0.225 for beach, or outdoor, balls.

Explanation:

did this help?

4 0
3 years ago
A sample of propane(c3h8)has 3.84x10^24 H atoms.
deff fn [24]

Answer:

A) 14. 25 × 10²³ Carbon atoms

B) 34.72 grams

Explanation:

1 molecule of Propane has 3 atoms of Carbon and 8 atoms of Hydrogen.

The sample has 3.84 × 10²⁴ H atoms.

If 8 atoms of Hydrogrn are present in 1 molecule of propane.

3.84 × 10²⁴ H atoms are present in

\mathfrak{ \frac{3.8 }{8} \times 10 ^{24}}

<u>= 4.75 × 10²³ molecules of Propane</u>.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

No. of Carbon atoms in 1 molecule of propane = 3

=> C atoms in 4.75× 10²³ molecules of Propane = 3 × 4.75 × 10²³

<u>= 14.25 × 10²³ </u>

<u>________________________________________</u>

<u>Gram</u><u> </u><u>Molecular</u><u> </u><u>Mass</u><u> </u><u>of</u><u> </u><u>Propane</u><u>(</u><u>C3H8</u><u>)</u>

= 3 × 12 + 8 × 1

= 36 + 8

= 44 g

1 mole of propane weighs 44g and has 6.02× 10²³ molecules of Propane.

=> 6.02 × 10²³ molecules of Propane weigh = 44 g

=> 4. 75 × 10²³ molecules of Propane weigh =

\mathsf{ \frac{44 }{6.02 \times  {10}^{23} } \times 4.75 \times  {10}^{23}  }

\mathsf{  = \frac{44 }{6.02 \times   \cancel{{10}^{23} }} \times 4.75 \times \cancel{ {10}^{23}}  }

\mathsf{  = \frac{44 }{6.02 } \times 4.75   }

<u>= 34.72 g</u>

8 0
2 years ago
2 HCl + Na2SO4 &gt; 2 NaCl + H2SO4
Cerrena [4.2K]

Answer:

15

Explanation:

8 0
2 years ago
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