Answer:
x = 5
Step-by-step explanation:
x + 5 = {Midpoint theorem}
2(x+ 5) = x² - x
2x + 10 = x² - x
x² - x - 2x - 10 = 0
x² - 3x - 10 = 0
x² - 5x + 2x - (5*2) = 0
x(x - 5) + 2(x - 5) = 0
(x -5)(x + 2) = 0
{x + 2 is ignored because measurement could not be in negative value}
x - 5 = 0
x = 5
Answer:
(a) F(A, B, C) = AB'C' + A'BC' + A'B'C
(b) F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)
Step-by-step explanation:
(a) If F(A, B, C) = 1 iff exactly one of the coins is heads, then either
A is heads and the others are tails (AB'C')
B is heads and the others are tails (A'BC')
C is heads and the others are tails (A'B'C)
Hence, as a minterm expansion,
F(A, B, C) = AB'C' + A'BC' + A'B'C
(b) To get the corresponding maxterm expansion, we convert to binary.
The maxterm is the product of the complements.
Expanding,
F(A, B, C) = (A' + B' + C')(A' + B + C)(A + B' + C)(A + B + C')(A + B + C)