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2 years ago

Im trying to get in fresman honors science so i want to make sure i get this right.

Chemistry

2 answers:

Ratling [72]2 years ago

4 0

Answer:

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2). Acceleration is also a vector quantity, so it includes both magnitude and direction.

Explanation:

Sunny_sXe [5.5K]2 years ago

3 0

Answer:

<h2>∞∞∞∞∞∞║Δ║Hello Friend║Δ║∞∞∞∞∞∞</h2>

Your answer should be:

1. Acceleration is the name we give to any process where the velocity changes. Since velocity is a speed and a direction, there are only two ways for you to accelerate: change your speed or change your direction—or change both.

If you’re not changing your speed and you’re not changing your direction, then you simply cannot be accelerating—no matter how fast you’re going. So, a jet moving with a constant velocity at 800 miles per hour along a straight line has zero acceleration, even though the jet is moving really fast, since the velocity isn’t changing. When the jet lands and quickly comes to a stop, it will have acceleration since it’s slowing down.

2. True (Because if you subtract the final speed to the initial speed, you can see how much acceleration you put on or took off.

Explanation:

<em>Brainliest would be appreciated! </em>

<h2><em>Have a great day! Hope this helps!</em></h2>

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If 4.12 l of a 0.850 m-h3po4 solution is be diluted to a volume of 10.00 l, what is the concentration of the resulting solution?

statuscvo [17]

The process in which the concentration of the solution is lessened by the addition of water is said to be dilution and equation of dilution relates the initial concentration and volume of stock solution with the final concentration and volume of the solution.

Formula is given by:

$C_{1}V_{1}=C_{2}V_{2}$ (1)

where,

$C_{1}$ is the initial concentration

$V_{1}$ is the initial volume

$C_{2}$ is the final concentration

$V_{2}$ is the final volume

Now,

$C_{1}$ = 0.850 M

$V_{1}$ = 4.12 L

$C_{2}$ =?

$V_{2}$ = 10.00 L

Substitute the give values in formula (1),

$0.850 M\times 4.12L=C_{2}\times 10.00 L$

$C_{2} =\frac{0.850 M\times 4.12L}{10.00 L}$

= $0.3502 M$

Thus, the final concentration of the $H_{3}PO_{4}$ solution = $0.3502 M$

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2 years ago

All chemical reactions need the same amount of activation energy.<br> A<br> True

Blizzard [7]

Answer:
false

explanation:
it is possible to lower the amount of activation energy required in a system. the process of speeding up a reaction by reducing its activation energy is known as catalyst.

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2 years ago

Please help i got no clue how to do dis

mamaluj [8]

Answer:

Sulfur's Atomic #: 16

Fluorine's Atomic #: 9

Antimony's Atomic #: 51

Silver's Atomic #: 47

Rubidium's Atomic #: 37

Copper's Atomic #: 29

Tin's Atomic #: 50

Mercury's Atomic #: 80

Promethium's Atomic #: 61

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Answer:

thanks for the points have a nice day :D

Explanation:

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