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Blababa [14]
3 years ago
8

What is target heart rate? Why is it important for a soccer player to reach target heart rate during training, and what activiti

es should be included in a training program to ensure this happens? FOR PE!!!!!!!
Physics
1 answer:
shepuryov [24]3 years ago
3 0

Answer:

While HR responses are between 152 to 184 bpm in SSGs (from 1-a-side to 8-a-side) [15,16,17], HR during soccer match play averages 150 to 180 bpm [5,18,19], corresponding to 85% of maximum heart rate (HRmax) [20].

While HR responses are between 152 to 184 bpm in SSGs (from 1-a-side to 8-a-side) [15,16,17], HR during soccer match play averages 150 to 180 bpm [5,18,19], corresponding to 85% of maximum heart rate (HRmax) [20].

Explanation:

I hope it will be helpful to you! can u pls make me as brainliest.

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A model train moves 18.3m in 122s. What is the train's average speed?
Kisachek [45]

Answer:0.15 m/sec

Explanation:

To calculate speed you use distance over speed

18.3/122= 0.15

5 0
3 years ago
G of potassium reacts with 16 g of oxygen to produce 94 g of potassium oxide
Vanyuwa [196]

Answer:

78g

Explanation:

Given parameters:

Mass of oxygen gas = 16g

Mass of potassium oxide = 94g

Unknown:

Mass of reacting potassium = ?

Solution:

To solve this problem, we need to obtain a balanced reaction equation. Then determine the number of moles of the reactant and use it to find that of the other one.

Balanced equation:

                      4K +   O₂   →    2K₂O

  Number of moles of reacting oxygen;

       Number of moles = \frac{mass}{molar mass}

molar mass of  O₂ = 2 x 16 = 32g/mole

     Number of moles = \frac{16}{32}  = 0.5mole

From the reaction equation;

          4 mole of K reacted with 1 mole of O₂;

           x mole of K will react with 0.5 mole of O₂

Therefore, 4 x 0.5 = 2 moles of potassium.

Mass of potassium = number of moles x molar mass

              Molar mass of potassium = 39g

Mass of potassium = 2 x 39 = 78g

5 0
3 years ago
A mass of 2 kg is attached to a spring and placed on a horizontal surface. The spring has a spring constant of 20 N/m, and the s
Sergio [31]

The speed of the mass : <em><u>v = 0.316 m/s</u></em>

<h3>Further explanation</h3>

The energy used to press a spring is included as the potential energy

Can be formulated:

\displaystyle E_p=\frac{1}{2}kx^2

Ep= potential energy

k = spring constant

x = change in spring length

If the spring is released from its pressure, this potential energy will turn into kinetic energy

so applies the law of conservation of mechanical energy (Em)

Ek = Ep

A mass of 2 kg is attached to a spring, a spring constant of 20 N/m, and the spring is compressed 0.1 m past its natural length.

m = 2 kg

k = 20 N/m

x = 0.1 m

\displaystyle Ep=Ek\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\kx^2=mv^2\\\\20\times0.1^2=2\times v^2\\\\v^2=0.1\\\\v=\sqrt{0.1}\\\\v=0.316~m/s

<h3>Learn more</h3>

Hooke's law

brainly.com/question/2648431

Keywords : spring,mass, spring constant,compressed position

5 0
4 years ago
How long has eggs been around
Paraphin [41]

Answer:

About six million years

Explanation:

3 0
3 years ago
Read 2 more answers
II Force on a tennis ball. The record speed for a tennis ball that is served is 73.14 m/s. During a serve, the ball typically st
AveGali [126]

Answer:

F=248.5W N

Explanation:

Newton's 2nd Law tells us that F=ma. We will use their averages always. The average acceleration the tennis ball experimented is, by definition:

a=\frac{\Delta x}{\Delta t}=\frac{v-v_0}{t-t_0}

Since we start counting at 0s and the ball departs from rest, this is just a=\frac{v}{t}

So we can write:

F=ma=\frac{mv}{t}=\frac{gmv}{gt}

Where in the last step we have just multiplied and divided by g, the acceleration of gravity. This allows us to introduce the weight of the ball W since W=gm, so we have:

F=\frac{Wv}{gt}=\frac{v}{gt}W

Substituting our values:

F=\frac{(73.14m/s)}{(9.81m/s^2)(30\times10^{-3}s)}W=248.5W N

Where the average force exerted has been written it terms of the tennis ball's weight W.

8 0
3 years ago
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