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avanturin [10]
2 years ago
12

HELP I NEED THIS ASAPON THE IMAGE​

Chemistry
2 answers:
Andrew [12]2 years ago
8 0

Explanation:

This is the answer--------

Sunny_sXe [5.5K]2 years ago
7 0

Answer:

hope you find it helpful

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What is the mass of 4 moles of helium, He?
aniked [119]
I am pretty sure it is 4.002602
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3 years ago
As the number of carbons increases in an homologous series the melting and boiling point generally_________ *
Oliga [24]
ANSWER: Increase


why? Because the number of C atoms in homologous series increases gradually.
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Magnesium (Mg): 1s22s22p63s2<br><br> longhand notation<br><br> noble-gas notation
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What did Ernest Rutherford’s gold foil experiment demonstrate about atoms ?
Alchen [17]

Answer:

Their positive charge is located in the small nucleus

Explanation:

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3 years ago
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g Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.71 g of ethane i
Kamila [148]

Answer:

6.05g

Explanation:

The reaction is given as;

Ethane + oxygen --> Carbon dioxide + water

2C2H6 + 7O2 --> 4CO2 + 6H2O

From the reaction above;

2 mol of ethane reacts with 7 mol of oxygen.

To proceed, we have to obtain the limiting reagent,

2,71g of ethane;

Number of moles = Mass / molar mass = 2.71 / 30 = 0.0903 mol

3.8g of oxygen;

Number of moles = Mass / molar mass = 3.8 / 16 = 0.2375 mol

If 0.0903 moles of ethane was used, it would require;

2 = 7

0.0903 = x

x = 0.31605 mol of oxygen needed

This means that oxygen is our limiting reagent.

From the reaction,

7 mol of oxygen yields 4 mol of carbon dioxide

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7 = 4

0.2375 = x

x = 0.1357

Mass = Number of moles * Molar mass = 0.1357 * 44 = 6.05g

8 0
3 years ago
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