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adoni [48]
3 years ago
8

What did Ernest Rutherford’s gold foil experiment demonstrate about atoms ?

Chemistry
2 answers:
Alchen [17]3 years ago
4 0

Answer:

Their positive charge is located in the small nucleus

Explanation:

Ernest Rutherford performed the gold foil experiment in 1911 where he used alpha particles generated from a radioactive source to bombard a thin gold foil.

In his experiment, he observed that the bulk of the alpha particles passed through the gold foil, just a tiny fraction was deflected back. To explain his findings, Rutherford proposed that an atom is made of positively charged centre where nearly all the mass is concentrated called nucleus. Surrounding the nucleus is a large space containing electrons.

worty [1.4K]3 years ago
4 0

He discovered that other than the nucleus at the center, atoms are mostly just empty space. So A makes the most sense.

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What type of ion does neutral produces
Yuki888 [10]

Answer:

Neutral ions

Explanation:

Because they have a neutral charge They can only produce neutrally.

4 0
4 years ago
Match each chemical with the correct use.
Fittoniya [83]

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3. anesthetic-  nitrous oxide  

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7 0
4 years ago
The electrostatic attraction between positively charged nuclei and negatively charged electrons permits two atoms to be held tog
Serggg [28]

Answer:

The correct answer is a. chemical bond. See the explanation below, please.

Explanation:

The resulting electrostatic interaction is called ionic bond between ions of opposite charge (one negative and one positive). This allows the attraction between both charges, constituting a chemical compound. Eg the Sodium (Na +) ion combines with the Chlorine (Cl-) ion forming Nacl (sodium chloride, known as table salt).

6 0
3 years ago
A ground state hydrogen atom absorbs a photon of light having a wavelength of 92.05 nm. It then gives off a photon having a wave
vodka [1.7K]
Absorbed photon energy
Ea = hc/λ.. (Planck's equation)
Ea = hc / 92.05^-9m 

<span>Energy emitted
Ee = hc/ 1736^-9m </span>

Energy retained ..
∆E = Ea - Ee = hc(1/92.05<span>^-9 - 1/1736^-9) </span>
<span>∆E = (6.625^-34)(3.0^8) (1.028^7)
∆E = 2.04^-18 J </span>

<span>Converting J to eV (1.60^-19 J/eV)
 ∆E = 2.04^-18 / 1.60^-19
∆E = 12.70 eV </span>

<span>Ground state (n=1) energy for Hydrogen = - 13.60eV </span>

<span>New energy state = (-13.60 + 12.70)eV = -0.85 eV </span>

<span>Energy states for Hydrogen
En = - (13.60 / n²) </span>

n² = -13.60 / -0.85 = 16
n = 4
4 0
3 years ago
How many grams are in 1.46 mol K2O?
CaHeK987 [17]

Answer:

94.196 grams

Explanation:

6 0
3 years ago
Read 2 more answers
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