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tangare [24]
2 years ago
6

Find the mass in kilograms of the liquid air that is required to produce 600L of oxygen. In normal condition, 1L of liquid air h

as 1.3g​
Chemistry
2 answers:
Step2247 [10]2 years ago
8 0

Explanation:

1L is 1.3 g so 600L is 780 g

1kg= 1000g so

780 g = 0.78kg

I GUESS

IgorC [24]2 years ago
3 0

Mass in kilograms of liquid air required = 0.78 kg

<u>Given that </u>

1 Litre of liquid air contains 1.3 grams of oxygen ( air )

<u />

<u> Determine the a</u><u>mount of liquid air</u><u> in Kg</u>

volume of air given = 600 L

mass of liquid air required = x

1 litre = 1.3 grams

600 L =  x

∴ x ( mass of liquid air ) = 1.3 * 600

                                       = 780 g  = 0.78 kg

Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg

Learn more about liquid air : brainly.com/question/636295

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