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tangare [24]
2 years ago
6

Find the mass in kilograms of the liquid air that is required to produce 600L of oxygen. In normal condition, 1L of liquid air h

as 1.3g​
Chemistry
2 answers:
Step2247 [10]2 years ago
8 0

Explanation:

1L is 1.3 g so 600L is 780 g

1kg= 1000g so

780 g = 0.78kg

I GUESS

IgorC [24]2 years ago
3 0

Mass in kilograms of liquid air required = 0.78 kg

<u>Given that </u>

1 Litre of liquid air contains 1.3 grams of oxygen ( air )

<u />

<u> Determine the a</u><u>mount of liquid air</u><u> in Kg</u>

volume of air given = 600 L

mass of liquid air required = x

1 litre = 1.3 grams

600 L =  x

∴ x ( mass of liquid air ) = 1.3 * 600

                                       = 780 g  = 0.78 kg

Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg

Learn more about liquid air : brainly.com/question/636295

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Container A holds 717 mL of an ideal gas at 2.80 atm. Container B holds 174 mL of a different ideal gas at 4.30 atm. Container A
horsena [70]

Answer:

3.09 atm

Explanation:

Given that:

Volume of container A = 717 mL

Pressure of container A = 2.80 atm

Volume of container B = 174 mL

Pressure of container B = 4.30 atm

Now, if the valve are being removed and the gases are allowed to mix together; then

The total final pressure can be calculated by using the formula:

P_f = \dfrac{P_AVA+P_BV_B}{V_A+V_B}

P_f = \dfrac{2.80*717+4.30*174}{717+174}

P_f = \dfrac{2007.6+748.2}{891}

P_f = \dfrac{2755.8}{891}

\mathbf{P_f =3.09 \ atm}

4 0
3 years ago
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A mixture has lots of different elements that are not necessarily bonded to each other, like sea water has lots of dirt, animals, and plant parts in it.  Compared to a solution (strictly salt and water, which bond and ionize with each other).
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The smallest unit of an element
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The smallest unit of an element that retains the chemical and physical properties of an element is an Atom.
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What is the correct answer?
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