Find the mass in kilograms of the liquid air that is required to produce 600L of oxygen. In normal condition, 1L of liquid air h

Question

2 years ago

6

as 1.3g

2 answers:

Step2247 [10] · Answer 1 · 2023-03-21T22:09:39+03:00

8 0

Explanation:

1L is 1.3 g so 600L is 780 g

1kg= 1000g so

780 g = 0.78kg

I GUESS

IgorC [24] · Answer 2 · 2023-03-21T20:33:01+03:00

Mass in kilograms of liquid air required = 0.78 kg

Given that

1 Litre of liquid air contains 1.3 grams of oxygen ( air )

Determine the amount of liquid air in Kg

volume of air given = 600 L

mass of liquid air required = x

1 litre = 1.3 grams

600 L = x

∴ x ( mass of liquid air ) = 1.3 * 600

= 780 g = 0.78 kg

Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg

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