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tangare [24]
2 years ago
6

Find the mass in kilograms of the liquid air that is required to produce 600L of oxygen. In normal condition, 1L of liquid air h

as 1.3g​
Chemistry
2 answers:
Step2247 [10]2 years ago
8 0

Explanation:

1L is 1.3 g so 600L is 780 g

1kg= 1000g so

780 g = 0.78kg

I GUESS

IgorC [24]2 years ago
3 0

Mass in kilograms of liquid air required = 0.78 kg

<u>Given that </u>

1 Litre of liquid air contains 1.3 grams of oxygen ( air )

<u />

<u> Determine the a</u><u>mount of liquid air</u><u> in Kg</u>

volume of air given = 600 L

mass of liquid air required = x

1 litre = 1.3 grams

600 L =  x

∴ x ( mass of liquid air ) = 1.3 * 600

                                       = 780 g  = 0.78 kg

Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg

Learn more about liquid air : brainly.com/question/636295

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Explanation:

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4 0
2 years ago
What is the energy in joules of one photon of<br> microwaveradiation with a wavelength 0.122m?
pentagon [3]

<u>Answer:</u> The energy of photon is 162.93\times 10^{-26}J

<u>Explanation:</u>

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

E = energy of the light  = ?

h = Planck's constant  = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of photon = 0.122 m

Putting values in above equation, we get:

E=\frac{(6.626\times 10^{-34}Js)\times (3\times 10^8m/s)}{0.122m}\\\\E=162.93\times 10^{-26}J

Hence, the energy of photon is 162.93\times 10^{-26}J

3 0
3 years ago
How many moles are in 8.30x10^23 molecules of H2o
LUCKY_DIMON [66]
You multiply avogadro's number to what you were given.
8.30x10^23 * 6. 0221409x10^23
=1.357*10^25

That should be the right answer but I'm not sure. It has been awhile since I have done this.

4 0
2 years ago
Read 2 more answers
Item 4
Mariulka [41]

Answer:

c

Explanation:

8 0
3 years ago
A substance registers a temperature change from 20 to 40 to what incremental temperature change does this correspond
ss7ja [257]

<u>Given:</u>

Initial temperature, T1 = 20 C

Final temperature, T2 = 40 C

<u>To determine:</u>

The temperature change

<u>Explanation:</u>

Convert degree C to Kelvin

Temperature in Kelvin = degree C + 273

T1 = 20 + 273 = 293 K

T2 = 40 + 273 = 313 K

Incremental temperature change = T2 - T1 = 313-293 = 20 K

Ans: The temperature change in kelvin is 20 K

3 0
2 years ago
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