Answer:
Negative Radicals ---→
1).Flouride = F⁻
2). Chloride = Cl⁻
3) Bromide = Br⁻
4) Iodide = I⁻
5) Sulphate = SO₄²⁻
6) Oxide = O²⁻
7) Nitride = N³⁻
8) Sulphur = S²⁻
9) Carbide = C⁴⁻
10) Hydroxide = OH⁻
11) Nitrate = NO₃⁻
12) Carbonate = CO²⁻
13) Hydrogen Carbonate = HCO₃⁻
14) Sulphate = SO₄²⁻
15).Sulphite = SO₃³⁻
16) Nitrate = NO₃⁻
17)Nitrite = NO₂⁻
18) Hydrogen Sulphite = HSO₃⁻
19) Hydrogen Sulphate = HSO₄⁻
20) Chromate = CrO₄²⁻
There are lot of Radicals which cannot be easily written. Although some of the Important Radicals which are commonly used are mentioned above.
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Answer:
It is the way of cleaning of impurities present in metals
<u>Given:</u>
H2(g) + Cl2 (g) → 2HCl (g)
<u>To determine:</u>
The enthalpy of the reaction and whether it is endo or exothermic
<u>Explanation:</u>
Enthalpy of a reaction is given by the difference between the enthalpy of formation of reactants and products
ΔH = ∑nHf (products) - ∑nHf (reactants)
= [2Hf(HCl)] - [Hf(H2) + Hf(Cl2)] = 2 (-92.3) kJ = - 184.6 kJ
Since the reaction enthalpy is negative, the reaction is exothermic
<u>Ans:</u> The enthalpy of reaction is -184. kJ and the reaction is exothermic
Answer: Moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, 
.
Explanation:
Given: Mass of methane = 146.6 g
As moles is the mass of a substance divided by its molar mass. So, moles of methane (molar mass = 16.04 g/mol) are calculated as follows.
The given reaction equation is as follows.
This shows that 2 moles of hydrogen gives 1 mole of methane. Hence, moles of hydrogen required to form 9.14 moles of methane is as follows.
Thus, we can conclude that moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, .
