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2 years ago

PLEASE ANSWER I WILL MAKE BRAINLIEST!!!

2 answers:

4 0

They go out, in a series circuit all of the light bulbs are connected by a single wire, and when the light bulb gets removed it wouldn't be able to transfer the energy to the next light bulb.

The second part of that quiz is they stay lit, because all of the light bulbs are connected twice so if one is removed it will stay lit,

Hope this helps!

tangare [24]2 years ago

3 0

Using an example like Christmas lights, I would say yes because normally a lot of them would go out if one light is broken.

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How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)

Masteriza [31]

Answer: The amount of heat required to warm given amount of water is 470.9 kJ

Explanation:

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g$

To calculate the heat absorbed by the water, we use the equation:

$q=mc\Delta T$

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

$\Delta T$ = change in temperature = $T_2-T_1=(100-25)^oC=75^oC$

Putting values in above equation, we get:

$q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ$

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0

3 years ago

What volume of a 1.0 M HCl is required to completely neutralize 25.0 ml of a 1.0 M KOH?

kirza4 [7]

The question above can be solved by using this equation:
CAVA =CBVB
Where:
CA =Concentration of acid = 1.0 M
VA = Volume of acid = ?
CB = Concentration of base = 1.0 M
VB = Volume of base = 25 ml
VA = CBVB / CA
VA = [1 * 25] / 1 = 25 / 1 = 25
VA = 25 ml
Therefore, the volume of acid that is required to completely neutralize the base is 25 ml.

8 0

3 years ago

A compound is 57.1% oxygen and the remainder carbon. using oxygen as the standard (16 amu) and assuming a 1:1 atom ratio, calcul

Delicious77 [7]

Let's start with the amount given in percent. Let our basis be 100 grams of compound. So, that means that in this amount, 57.1 g is oxygen and 100-57.1=42.9 g is carbon. Since there is 1:1 atom ratio, it also means that moles oxygen = moles carbon.

Moles = Mass/Relative Mass
Let x be the relative mass of oxygen

57.1/16 = 42.9/x
Solving for x,
x = 12.02 amu

4 0

3 years ago

Select the correct answer.

rewona [7]

We can use the formula P=IV to calculate the current, where “P” is power (measured in watts), “I” is current (measured in Amps), and “V” is voltage. Simply plug and solve:

P = IV
(3.5 Watts) = I(120 volts)
I = 0.0292 Amps

The current flowing through the bulb is approximately 0.0292 Amps.

Hope this helps!

5 0

3 years ago

If the Kelvin temperature of a gas is doubled, the volume of the gas will increase by ____

liraira [26]

If the Kelvin temperature of a gas is doubled, the volume of the gas will increase by two. It follows Charles law where in for a mixed gas of mass, the volume is directly proportional to the temperature at constant pressure.

3 0

2 years ago