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Marrrta [24]
3 years ago
7

Iron (Fe) has three isotopes. Calculate the average atomic mass of the element Fe using the following data: Isotope atomic mass

(u) % abundance Fe-54 53.94 6% Fe-56 55.93 92% Fe-57 56.94 2%
Chemistry
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer:

Average atomic mass = 55.83 amu

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})+(\frac {\%\ of\ the\ third\ isotope}{100}\times {Mass\ of\ the\ third\ isotope})

Given that:

For first isotope, Fe-54:

% = 6 %

Mass = 53.94 amu

For second isotope, Fe-56:

% = 92 %

Mass = 55.93 amu

For third isotope, Fe-57:

% = 2 %

Mass = 56.94 amu

Thus,  

Average\ atomic\ mass=\frac{6}{100}\times {53.94}+\frac{92}{100}\times {55.93}+\frac{2}{100}\times {56.94}

<u>Average atomic mass = 55.83 amu</u>

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What is the % yield when 12g of Mg react with HCl to produce 0.2g of H2?
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Answer:

The yield is 20 %.

Explanation:

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(0.2 g) / (0.9953 g) = 0.20 = 20% yield

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Neither n2 nor o2 are greenhouse gases because
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7 0
2 years ago
Chromium(III) oxide can be prepared by heating chromium(IV) oxide in vacuo at high temperature: 4Cr02 —2Cr2O3 +02 The reaction o
kkurt [141]

<u>Answer:</u> The theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Given mass of CrO_2 = 480.1 g

Molar mass of CrO_2 = 84 g/mol

Putting values in equation 1, we get:

\text{Moles of }CrO_2=\frac{480.1g}{84g/mol}=5.72mol

For the given chemical equation:

4CrO_2\rightarrow 2Cr_2O_3+O_2

By Stoichiometry of the reaction:

4 moles of CrO_2 produces 2 moles of chromium (III) oxide

So, 5.72 moles of CrO_2 will produce = \frac{2}{4}\times 5.72=2.86mol of chromium (III) oxide

Now, calculating the mass of chromium (III) oxide from equation 1, we get:

Molar mass of chromium (III) oxide = 152 g/mol

Moles of chromium (III) oxide = 2.86 moles

Putting values in equation 1, we get:

2.86mol=\frac{\text{Mass of chromium (III) oxide}}{152g/mol}\\\\\text{Mass of chromium (III) oxide}=(2.86mol\times 152g/mol)=434.72g

To calculate the percentage yield of chromium (III) oxide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of chromium (III) oxide = 402.4 g

Theoretical yield of chromium (III) oxide = 434.72 g

Putting values in above equation, we get:

\%\text{ yield of chromium (III) oxide}=\frac{402.4g}{434.72g}\times 100\\\\\% \text{yield of chromium (III) oxide}=\%

Hence, the theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

7 0
3 years ago
What is the mass in grams of 8.65 mol C8H18?
aliina [53]

Answer:

m = 998 g

Explanation:

Hello there!

In this case, according to the definition of the molar mass as the mass of one mole of the compound, it is possible to state the 1 mole of C8H18 has a mass of 114.26 grams; therefore, the mass in 8.65 moles turn out to be:

m=8.65mol*\frac{114.26g}{1mol}\\\\m=998g

In agreement to the notation requirement.

Best regards!

5 0
3 years ago
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