Answer:
<span>In the addition of hbr to 1-butyne the electrophile in the first step of the mechanism is <u>Hydrogen atom of HBr</u>.
Explanation:
In this reaction first of all HBr approaches the triple bond. A Pi Complex (weak inter-molecular interactions) is formed between the two molecules. And the triple bond attacks the partial positive hydrogen atom creating a negative charge on Bromine along with positive charge on itself (Sigma Complex). In second step the negative Bromide attacks the positive carbon of Butyne.</span>
Answer:
= 1.60 L
Comment if you need step to step explanation.
4Li + O₂ = 2Li₂O
Li : Li₂O = 4 : 2 = 2 : 1
2 : 1
x : 4
x=4*2/1=8 mol
D) 8
