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3 years ago

The temperature at which a substance freezes is called its melting point. True or False

Chemistry

1 answer:

Reika [66]3 years ago

5 0

False it would be freezing point

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How is a chemical change different from a physical change?

DaniilM [7]

A physical change in a substance doesn't change what the substance is. In a chemical change where there is a chemical reaction, a new substance is formed and energy is either given off or absorbed.

6 0

3 years ago

Hydrogen peroxide can be prepared by the reaction of barium peroxide with sulfuric acid according to the reaction BaO2(s)+H2SO4(

Vesna [10]

Answer:

VH2SO4 = 145.3 mL

Explanation:

Mw BaO2 = 169.33 g/mol

⇒ mol BaO2 = 53.5g * ( mol BaO2 / 169.33 g BaO2) = 0.545 mol BaO2

⇒according to the reaction:

mol BaO2 = mol H2SO4 = 0.545 mol

⇒ V H2SO4 = 0.545 mol H2SO4 * ( L H2SO4 / 3.75 mol H2SO4 )

⇒V H2SO4 = 0.1453 L (145.3 mL)

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3 years ago

Read 2 more answers

Fill in the blank, please help. (55 points)

Degger [83]

The answer would be evaporation takes place at the surface of an ocean, lake, stream, or other body of water

7 0

3 years ago

21. _____ Which of the following entities has the greatest mass?

IrinaK [193]

I believe it’s D because phosphorus has the mass of 30.9.

8 0

3 years ago

A compound is determined to have the empirical formula C2OH4. If the molar mass of the compound is 132 g/mol, determine the mole

8_murik_8 [283]

Answer: The molecular formula will be $C_6O_3H_{12}$

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

Empirical weight of $C_2OH_{4}$ is $12\times 2+16\times 1+1\times 4=44g$

Molecular mass of compound is = 132 g

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{132}{44}=3$

The molecular formula will be= $3\times C_2OH_4=C_6O_3H_{12}$

5 0

3 years ago