Answer:
-10778.95 J heat must be removed in order to form the ice at 15 °C.
Explanation:
Given data:
mass of steam = 25 g
Initial temperature = 118 °C
Final temperature = 15 °C
Heat released = ?
Solution:
Formula:
q = m . c . ΔT
we know that specific heat of water is 4.186 J/g.°C
ΔT = final temperature - initial temperature
ΔT = 15 °C - 118 °C
ΔT = -103 °C
now we will put the values in formula
q = m . c . ΔT
q = 25 g × 4.186 J/g.°C × -103 °C
q = -10778.95 J
so, -10778.95 J heat must be removed in order to form the ice at 15 °C.
Answer:
1= Magnesium
2 = Option 3 = 1s² 2s² 2p⁶
Explanation:
An electrically neutral atom consist of equal number of protons and electrons.
The answer for 1st q is magnesium because the electronic configuration showed twelve number of electrons. The atomic number of magnesium is twelve that's why this configuration is of Mg.
Mg₁₂ = 1s² 2s² 2p⁶ 3s²
The second answer is option three because has atomic number ten and third electronic configuration have ten electrons.
Ne₁₀ = 1s² 2s² 2p⁶
It is stable electronic configuration. Neon is inert because of this electronic configuration. The outer most shell is completely filled.
Answer:
HCN < HOCl < HF
Explanation:
The larger the Kₐ value, the stronger the acid.
6.2 × 10⁻¹⁰ < 4.0 × 10⁻⁸ < 6.3 × 10⁻⁴
HCN < HOCl < HF
weakest stronger strongest
The answer is C. 146g because you add all of the masses of the individual elements and then mulyiply by 1.72 to get your answer.
