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belka [17]
2 years ago
5

A sealed 10.0 L flask at 400 K contains equimolar amounts of ethane and propanol in gaseous form. Which of the following stateme

nts concerning the average molecular speed of ethane and propanol is true?
(A) The average molecular speed of ethane is less than the average molecular speed of propanol.
(B) The average molecular speed of ethane is greater than the average molecular speed of propanol.
(C) The average molecular speed of ethane is equal to the average molecular speed of propanol.
(D) The average molecular speeds of ethane and propanol cannot be compared without knowing the total pressure of the gas mixture.
Chemistry
2 answers:
Phoenix [80]2 years ago
8 0

Answer:

(C) The average molecular speed of ethane is equal to the average molecular speed of propanol.

Explanation:

When dealing with gases, you know that the temperature and speed are related. When held at a constant temperature, the speed is also held constant. We also know that ideal gases behave the same despite their identities.

Fittoniya [83]2 years ago
5 0

Answer:

Im a 100% sure it is B. average molecular speed of ethane is greater than the average molecular speed of propanol.

Explanation:

Sry I didnt' get the explaination from my teacher.

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Let s = the molar solubility.  

                     AgIO₃(s) ⇌ Ag⁺(aq) + IO₃⁻(aq); Ksp = 3.0 × 10⁻⁸

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                     BaSO₄(s) ⇌ Ba²⁺(aq) + SO₄²⁻(aq); Ksp = 1.1 × 10⁻¹⁰

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C/mol·L⁻¹:                                 +s              +s

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\mu = \dfrac{1}{2} \sum_{i} {c_{i}z_{i}^{2}}\\\\\mu = \dfrac{1}{2} (\text{[Ba$^{2+}$]}\cdot (2+)^{2} + \text{[NO$_{3}$$^{-}$]}\times(-1)^{2}) = \dfrac{1}{2} (\text{0.02}\times 4 + \text{0.04}\times1)= \dfrac{1}{2} (0.08 + 0.04)\\\\= \dfrac{1}{2} \times0.12 = 0.06

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