Question

49.9 ml of a 0.00292 m stock solution of a certain dye is ddiluted to 1.00 L. the diluted solution has an absorbance of 0.600. what is the molar

Answer 1

Complete Question

49.9 ml of a 0.00292 m stock solution of a certain dye is diluted to 1.00 L. the diluted solution has an absorbance of 0.600. what is the molar absorptivity coefficient of the dye

Answer:

The  value is  $\epsilon = 4118.1 \ M^{-1} cm^{-1}$  

Explanation:

From the question we are told that

   The volume of the stock solution is  $V_1 = 49.9 mL = 0.0499 \ L$  

   The concentration of the stock solution is  $C_1 = 0.00292 \ M$

   The volume of the diluted solution is  $V_2 = 1.00 \ L$

   The absorbance is  $A = 0.600$

Generally the from the titration equation we have that

         $C_1 * V_1 = C_2 * V_2$

=>      $0.00292 * 0.0499 = C_2 * 1$

=>     $C_2 = 0.0001457 \ M$

Generally from  Beer's law we have that

      $A = \epsilon * l * C_2$

=>   $\epsilon = \frac{A}{ l * C_2 }$

Here  l is the length who value is  1 cm because the unit of  molar  absorptivity coefficient of the dye is $M^{-1} * cm^{-1}$

So

            $\epsilon = \frac{0.600}{ 1 * 0.0001457 }$  

=>       $\epsilon = 4118.1 \ M^{-1} cm^{-1}$