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2 years ago

Rutherford’s gold foil experiment demonstrated that

Chemistry

1 answer:

iVinArrow [24]2 years ago

4 0

Answer:

Explanation:

The space between the large nucleus and the electrons is huge. We know this because the alpha particles shot at the gold foil most went right on through. That means that the space between hold atoms is very large.

Not only that but the deflection that takes place is not frequent further telling us that the the nucleus must be positively charged. That observation comes from the deflection itself. The charge on the nucleus must be the same as the alpha particle. If they were different, and the nucleus was negative, those particles that were deflected would now be absorbed.

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Chemistry compound empirical formula and identify compounds weightWhich drug is c3 h3 01

valkas [14]

The drug C3H30 is called allenolate / 1-hydroxycyclopropyl

weight is 55.06g/mol

5 0

1 year ago

Using the periodic table as a reference, which elements could bond to form a compound most like NaCl?

pychu [463]

step by step

Na(sodium)=2.8.1

Cl (Chlorine)=2.8.7. sodium will give the chlorine the 1 valence electron to become stable ions.

answer

pottasium. (2.8.8.1) and Flourine(2.7)

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3 years ago

How many moles of calcium are there in 5.74 x 1022 atoms of calcium?

igor_vitrenko [27]

Answer:

0.095 moles of Calcium is there in 5.74 x 1022 atoms of calcium.

Explanation:

As we know, 6.023*10^23 atoms of an element is equal to its atomic weight.

And, 6.023*10^23 atoms of an element is also equal to 1 mole of the element.

We have,

6.023*10^23 atoms of element calcium equals to 1 mole of Calcium
5.74*10^22 atoms of element calcium equals to

(1/(6.023*10^.23)) * 5.74*10^22 moles of calcium

Therefore,

5.74 x 1022 atoms of calcium= 0.095 moles of calcium.

6 0

3 years ago

Correct name for #10 please

ira [324]

Answer:

CH₃CH(CH₃)CH(C₃H₇)CH₂CH(CH₃)₂:

4-isopropyl-2-methylpentane.

Explanation:

Step One: Draw the structure formula of this compound. Parentheses in the formula indicate substitute groups that are connected to the carbon atom to the left.

For example, the first (CH₃) indicates that the second carbon atom from the left is connected to:

the CH₃- on the left-hand side,
the -CH(C₃H₇)CH₂CH(CH₃)₂ on the right-hand side,
a hydrogen atom, and
an additional CH₃- group that replaced one hydrogen atom.

Each carbon atom in this compound is connected to four other atoms. All bonds between carbon atoms are single bonds.

The C₃H₇ in the second pair of parentheses is the condensed form of CH₃CH₂CH₂-. See the first sketch attached. Groups in parentheses are highlighted.

Step Two: Find the carbon backbone. The backbone of a hydrocarbon is the longest chain of carbon atoms that runs through the compound. See the second sketch attached. The backbone of this compound consists of seven carbon atoms and is highlighted in green. The name for this backbone shall be heptane.

Step Three: Identify and name the substitute groups.

The two substitute groups are circled in blue in the second sketch.

The one on the right -CH₃ is a methyl group.
The one on the left is branched. $\begin{aligned}\text{CH}_3-&\text{CH}-\text{CH}_3\\[-0.5em]&\;|\end{aligned}$ This group can be formed by removing one hydrogen from the central carbon atom in propane. The name for this group is isopropyl.

Step Four: Number the atoms.

Isopropyl shall be placed before methyl. Start from the right end to minimize the index number on all substitute groups. The methyl group is on carbon number two and the isopropyl group on carbon number four. Hence the name:

4-isopropyl-2-methylheptane.

5 0

3 years ago

How many molecules are in 10.0 miles of C2H6O

shutvik [7]

6.02 x 10²⁴ molecules of C2H6O

3 0

3 years ago