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3 years ago

Factor 54+2754+27 using the GCF. Whats the answer ??

1 answer:

7 0

When you look at the expression, 54 + 27, what do the two addends have in common?The first thing I notice is that 54 = 2(27), which means that 27 is a factor of both. Since, 27 is actually one of the addends, it's the greatest factor of 27 and therefore the greatest common factor. So,54 + 27 = 27(2+1)54 + 27 = 27(3)

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Find the equation in standard form of the line passing through the points 3,-4 and 5,1

aliina [53]

Answer:

5x - 2y - 23 = 0

Step-by-step explanation:

Line is passing through the points $(3,\:-4)= (x_1, \:y_1) \: \&\: (5,\: 1)= (x_2,\:y_2)$

Equation of line in two point form is given as:

$\frac{y -y_1 }{y_1 -y_2 } = \frac{x -x_1 }{x_1 -x_2 } \\ \\ \therefore \: \frac{y -( - 4) }{ - 4 -1} = \frac{x -3 }{3 -5 } \\ \\ \therefore \:\frac{y + 4 }{ - 5} = \frac{x -3 }{ - 2 } \\ \\ \therefore \: \frac{y + 4 }{ 5} = \frac{x -3 }{ 2 } \\ \\ \therefore \: 2(y + 4) = 5(x - 3) \\ \therefore \: 2y + 8 = 5x - 15 \\ \therefore \: 5x - 15 - 2y - 8 = 0 \\ \red{ \boxed{ \bold{\therefore \: 5x - 2y - 23 = 0}}} \\ is \: the \: required \: equation \: of \: line \: in \: \\ standard \: form.$

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3 years ago

A deck of cards contains RED cards numbered 1,2,3 and BLUE cards numbered 1,2,3,4,5,6. Let R be the event of drawing a red card,

Tatiana [17]

Answer:

e. R′

Step-by-step explanation:

Let the Sample Space be a universal set consisting of 3 red and 6 blue cards. Then the event of of getting 4 blue cards will be given

R complement = R` = Universal Set minus Red cards will give blue cards.

a. R OR O

It cannot be this option because we need 4 blue card

b. B AND O

It cannot be this choice as well because 4 is not odd.

c. R OR E

4 is even but we need blue

d. R AND O

Red and odd is again not required

e. R′ = It will give our required result.

f. E′= 4 is even if it is complemented it cannot be obtained and will be left out.

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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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