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emmainna [20.7K]
3 years ago
5

C=5x-3(4x-2(4x-3(5x-20))

Mathematics
1 answer:
stiv31 [10]3 years ago
5 0
The answer would be C = -73x + 360.
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Answer:

H=-(t-3)^2+13

Step-by-step explanation:

The path covered by the volleyball will be a downward parabola with the vertex being the highest point of the ball.

A general form of a downward parabola is given as:

y=-a(x-h)^2+k

Where (h,k) is the vertex of the parabola and 'a' is a constant.

Now, let 'h' be the vertical height and 't' be the time taken.

So, the equation would be of the form:

H=-a(t-h)^2+k

Now, as per question:

h = 2 seconds, k = 13 feet.

H=-a(t-3)^2+13

Now, taking a = 1. So, the formula that can be used is:

H=-(t-3)^2+13

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If line TW is parallel to line SX , m ∠ 1 = 59°, and m ∠ 6 = 72°, what is m ∠ 8?
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Angle 1 and Angle 8 are Alternate Exterior Angles. Therefore, by the Alternate Exterior Angle Theorem, the measure of angle 8 is also 59 degrees. Hope this helped!
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What is 1/10 of 0.04
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Step-by-step explanation:

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