Do rise/run and u should have your answer
Answer:
Part 1) The lateral area is ![LA=791.7\ ft^{2}](https://tex.z-dn.net/?f=LA%3D791.7%5C%20ft%5E%7B2%7D)
Part 2) The surface area is ![SA=1,244.1\ ft^{2}](https://tex.z-dn.net/?f=SA%3D1%2C244.1%5C%20ft%5E%7B2%7D)
, ![SA=1,244.1\ ft^{2}](https://tex.z-dn.net/?f=SA%3D1%2C244.1%5C%20ft%5E%7B2%7D)
Step-by-step explanation:
step 1
Find the lateral area of the cone
we know that
The lateral area of the cone is equal to
![LA=\pi rl](https://tex.z-dn.net/?f=LA%3D%5Cpi%20rl)
we have
![r=12\ ft](https://tex.z-dn.net/?f=r%3D12%5C%20ft)
![l=21\ ft](https://tex.z-dn.net/?f=l%3D21%5C%20ft)
substitute
![LA=(3.1416)(12)(21)=791.7\ ft^{2}](https://tex.z-dn.net/?f=LA%3D%283.1416%29%2812%29%2821%29%3D791.7%5C%20ft%5E%7B2%7D)
step 2
Find the surface area of the cone
we know that
The surface area of the cone is equal to
![SA=\pi r^{2}+LA](https://tex.z-dn.net/?f=SA%3D%5Cpi%20r%5E%7B2%7D%2BLA)
we have
![r=12\ ft](https://tex.z-dn.net/?f=r%3D12%5C%20ft)
![LA=791.7\ ft^{2}](https://tex.z-dn.net/?f=LA%3D791.7%5C%20ft%5E%7B2%7D)
substitute
![SA=(3.1416)(12)^{2}+791.7=1,244.1\ ft^{2}](https://tex.z-dn.net/?f=SA%3D%283.1416%29%2812%29%5E%7B2%7D%2B791.7%3D1%2C244.1%5C%20ft%5E%7B2%7D)
Answer:
1,220,703,125
Step-by-step explanation:
Honestly don't know how to explain this in any other way than just saying put it in a calculator. Sorry. :p
Answer:So you need to calculate a weighted average, where the average of 70 has twice the weight of the average of 85 (20 students vs 10). The easiest way to think about it is to split the 20 into two groups of 10 so that you have three groups of 10 students, that way you can just average the scores as normal.
So, you have three averages of 85, 75 and 75.
Total average = (85+75+75)/3 = 78.33... hopes this helps
Answer:
The temperature on Tuesday was 13.3 degrees Celcius, 3 degrees less than that of Monday.
Step-by-step explanation:
Given that the temperature on Monday was 16.3 degrees Celsius, and the following Tuesday the temperature dropped about 3 degrees, to determine the temperature of that day the following calculation must be made:
16.3 - 3 = X
13.3 = X
Thus, the temperature on Tuesday was 13.3 degrees Celcius, 3 degrees less than that of Monday.