Question

When the 3.0 kg cylinder fell 500 m, the final temperature of the water was

Answer 1

Answer:

Change in temperature =7.14° C

Explanation:

Assuming all potential energy of cylinder is converted into heat energy to increase the temperature .

Work done by gravity in first case =m *g*h= 3*10*500=15000

Let quantity of water be 1 kg at 0°C.

Also specific heat capacity of water is =4200 Joule

So potential energy is converted to m*4200*T(1) =15000

                      T(1)=3.57

Work done by gravity in first case =m *g*h= 9*10*500=45000

Here also potential energy is converted into m*4200*T(2)=45000

                    T(2)=10.71

Here temperature is increasing.

Thus change in temperature =T(1) -T(2) =7.14° C