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Juli2301 [7.4K]
3 years ago
9

Who knows that?????????

Mathematics
1 answer:
Alecsey [184]3 years ago
3 0

Answer:

normally 15 seats in 1 row so 15 X 10= 150

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If your heart beats 80 times per minute and you live to be 90 years old, estimate the number of times your heart beats during yo
umka2103 [35]

The heart beat is given in units of beats per minute, therefore before we can do any calculations let us make sure that all units are similar by converting the age in terms of minutes.

We know that there are 365 days per year, therefore:

90 years (365 days / year) = 32,850 days

We know that in a day, there are 24 hours, therefore:

32,850 days (24 hours / day) = 788,400 hours

And in an hour, there are 60 minutes, therefore:

788,400 hours (60 minutes / hour) = 47,304,000 minutes

 

Now calculating for the total heart beats in a lifetime:

total heartbeats = (80 beats / minute) * 47,304,000 minutes

total heartbeats = 3,784,320,000

 

Writing this into scientific notation:

3.78 x 10^9 beats

or

<span>3.8 x 10^9 beats</span>

8 0
3 years ago
Of the 45 animals on the farm, there are only pigs and chickens. The animals have a total of 124 legs. How many pigs and how man
Bess [88]

Answer:

on \: this \: farm \: there \: are \to \\  \underline{ \boxed{17 \: pigs }}\:  \\  and \\  \underline{ \boxed{28 \:chickens}}

Step-by-step explanation:

\\  \underline{ \boxed{solution \: to \: question \:  \boxed{ A}}} \\ \\ let \: the \: pigs \: be \to \: p \\ let \: the \: chicks \: be \to \: c \\let \: the \: total \: animals \: be \to \: 45 \\  hence \to \\ p + c = 45.......eq(1) \\ since \: chickens \: have \: two \: legs : \\  while \: pigs \: have \: four \: legs : \\ let \: animals \: with \: 2 \: legs \: be \to \: 2c \\ let \: animals \: with \: 4\: legs \: be \to \: 4p \\ the \: total \: number \: of \: animal \: legs  = 124 \\ hence \to \\ 4p + 2c = 124..........eq(2) \\ therefore \: the \: system \:  of \:  equations \: \\   to  \: describe  \: the  \: situation \: is \to \\ \\  p + c = 45 \\ 4p + 2c = 124 \\  \\  \\ \underline{ \boxed{solution \: to \: question \:  \boxed{B }}} \\  \\  \\ we \: could \: apply \: any \: of \: the \: simultanious \\  principles \to \\ here : am \: appling \: the \: elimination \: method   \to \\ p + c = 45 \\ 4p + 2c = 124  \\ to \: elimnate \: one \: varaible \: we \: multiply \: by \to \\ (4) \times p + c = 45 \\ (1) \times 4p + 2c = 124  \\ hence \to \\   - \frac{4p + 4c = 180}{4p + 2c = 124}  \\next \to \\   2c = 56 \\ c =  \frac{56}{2}  \\ \boxed{ c = 28} \\ lets \: work \: for \: p \to \\ p + c = 45 \\ p + 28 = 45 \\ p = 45 - 28 \\  \boxed{p = 17}

6 0
3 years ago
Need a little help!!!
telo118 [61]
The answer is 615.44
3 0
2 years ago
Calculate the output for f(x) = 3x-1 when the input is x=14
Kryger [21]

Answer:

41

Step-by-step explanation:

<u>3(14)</u>-1

<u>42-1</u>

41

4 0
3 years ago
Read 2 more answers
Multiply o binomial by a trinomial<br>(x-1) (x²+x+1)<br>​
Marizza181 [45]

Answer:

Is this helpful or wrong?

4 0
3 years ago
Read 2 more answers
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