Answer:
The answer would be nine
Explanation:
59 divided by 7 is 8 with 3 remaning but all must be included so you have anothr crate for the remaining the and sice 8+1=9. Velma needs 9 crates. Hope this Helps!!
Answer:
y = -24 + -2x + 2x2
Step-by-step explanation:
Simplifying:
y = 2(x + 3)(x + -4)
reorder the terms:
y = 2(3 + x)(x + -4)
multiply (3 + x) * (-4 + x)
y = 2(3(-4 + x) + x(-4 + x))
y = 2((-4 * 3 + x * 3) + x(-4 + x))
y = 2((-12 + 3x) + x(-4 + x))
y = 2(-12 + 3x + (-4 * x + x * x))
y = 2(-12 + 3x + (-4x + x2))
Combine like terms 3x + -4x = -1x
y = 2(-12 + -1x + x2)
y = (-12 * 2 + -1x * 2 + x2 * 2)
y = (-24 + -2x + 2x2)
Solving:
y = -24 + -2x + 2x2
solving for variable 'y'
Move all terms containing y to the left, all other terms to the right.
Simplifying:
y = -24 + -2x + 2x2
Answer:
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
Step-by-step explanation:
Given
Volume of a box = length × breadth × height= l×b×h
In this case the box have a square base. i.e l=b
Volume V = l^2 × h
The surface area of a square box
S = 2(lb+lh+bh)
S = 2(l^2 + lh + lh) since l=b
S = 2(l^2 + 2lh)
Given that the box is open top.
S = l^2 + 4lh
And Surface Area of the box is 1200cm^2
1200 = l^2 + 4lh ....1
Making h the subject of formula
h = (1200 - l^2)/4l .....2
Volume is given as
V = l^2 × h
V = l^2 ×(1200 - l^2)/4l
V = (1200l - l^3)/4
the maximum point is at dV/dl = 0
dV/dl = (1200 - 3l^2)/4
dV/dl = (1200 - 3l^2)/4 = 0
3l^2= 1200
l^2 = 1200/3 = 400
l = √400
I = 20cm
Since,
h = (1200 - l^2)/4l
h = (1200 - 20^2)/4×20
h = (800)/80
h = 10cm
The largest possible volume V is ;
V = l^2 × h
V = 20^2 × 10 = 4000cm^3
There are 16 3/8 in 6 inches
Answer:
Smith
Step-by-step explanation:
Woodson has fewer than Smith
Smith>Woodson
Woodson has more than Rodriquez
Smith>Woodson>Rodriguez
Blackburn has fewer then Rodriguez
Smith>Woodson>Rodriguez>Blackburn
