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Arlecino [84]
3 years ago
8

Please don’t use any links they don’t work.

Mathematics
1 answer:
Rudiy273 years ago
5 0
The answer is 5/15.
Here is why:
So we know that the sum has to be greater than or equal to 8/15.
When adding 1/15 to 2/15 you get 3/15 which is less than 8/15 so it’s not the answer. Then 8/30 = 4/15. 4/15+2/15=6/15 which is less than 8/15 so it’s not the answer. Thirdly, 5/15+2/15= 7/15 which is less than 8/15 so it’s not the answer. Lastly, 8/15+2/15= 10/15 which is larger than 8/15 so it is greater than 1/2 so it is the answer. The answer is d
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Is it 1 solution, no solution or infinite solution? <br> -28 = -7(3x + 4) + 21
prohojiy [21]

x = 1 because -7(3x + 4) must be -49 so 3x + 4 must me 7 so x = 1

5 0
4 years ago
One side of a parallelogram has endpoints (3, 3) and (1, 7).. . What are the endpoints for the side opposite?. . . . (8, 1) and
tino4ka555 [31]

The endpoints for the opposite side would be (8, 1) and (6, 5). The correct answer between all the choices given is the last choice. I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.

3 0
3 years ago
Read 2 more answers
Hey i needed help with this scale factor
WITCHER [35]
X=16
Divide 44 by 11 you get 4
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Multiply 4 and 4
7 0
2 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
ddd [48]

Answer:

f'(x) = 4x^2 - 3 for x \le -3

Step-by-step explanation:

See attachment for proper question

Given

f(x) = -\frac{1}{2}\sqrt{x + 3}

For

x \ge -3

Required

Determine the inverse function

f(x) = -\frac{1}{2}\sqrt{x + 3}

Replace f(x) with y

y = -\frac{1}{2}\sqrt{x + 3}

Swap the positions of x and y

x = -\frac{1}{2}\sqrt{y + 3}

Multiply both sides by -2

-2 * x =-2 *  -\frac{1}{2}\sqrt{y + 3}

-2x =\sqrt{y + 3}

Square both sides

(-2x)^2 =(\sqrt{y + 3})^2

4x^2 =y + 3

Make y the subject

y = 4x^2 - 3

The inverse has been solved. So, we need to replace y with f'(x)

f'(x) = 4x^2 - 3

Next, is to determine the interval

x \ge -3

Change inequality to \le

x \le -3

Hence, the inverse function is:

f'(x) = 4x^2 - 3 for x \le -3

7 0
3 years ago
Expand and simplify (3x+4)(2x+3)
d1i1m1o1n [39]

Answer:

72 you just need to keep multiplying

Step-by-step explanation:

3x4. 2x3

12 x 6

72

3 0
3 years ago
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