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Ne4ueva [31]
3 years ago
11

In order to solve this equation for x, the first step is to subtract 6 from both sides.

Mathematics
2 answers:
Tcecarenko [31]3 years ago
7 0
True. You would end up with 3x=36
telo118 [61]3 years ago
3 0
The statement is true.
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Divide 28 cans of soda into two groups so the ratio is 3 to 4<br>to
Brums [2.3K]
28 = 3x+4x 
x = 4 

3x = 12 
4x = 16 
12:16 = 3:4
6 0
3 years ago
PLEASE HELP QUICK!!!! What is the degree of 7x^6 - 6x^5 + 2x^3 + x - 8? A. 8 B. 7 C. 5 D. 6
antiseptic1488 [7]
For determining the correct degree of a polynomial, you need to look at each term and find the degree by adding the exponents of each variable in it. The largest degree is the degree of the polynomial.

7x^6 has largest degree of the given polynomial, so your answer is D.6
5 0
3 years ago
Walter buys a bus pass for $30 every time he rides the bus money is deducted from the value of the pass he rode 12 times and $24
klemol [59]
So each time, 24/12 or $2 was deducted per trip

he has 30-24=$6 left

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6 0
3 years ago
Please solve quickly ​
Alex Ar [27]

Answer:

77 inches

Step-by-step explanation:

sector formula = x°/360° × πr^2

=77°/360°×22/7×10.7×10.7

=76.96 in

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7 0
1 year ago
Read 2 more answers
Find the derivative of the function at P 0 in the direction of A. ​f(x,y,z) = 3 e^x cos(yz)​, P0 (0, 0, 0), A = - i + 2 j + 3k
Alik [6]

The derivative of f(x,y,z) at a point p_0=(x_0,y_0,z_0) in the direction of a vector \vec a=a_x\,\vec\imath+a_y\,\vec\jmath+a_z\,\vec k is

\nabla f(x_0,y_0,z_0)\cdot\dfrac{\vec a}{\|\vec a\|}

We have

f(x,y,z)=3e^x\cos(yz)\implies\nabla f(x,y,z)=3e^x\cos(yz)\,\vec\imath-3ze^x\sin(yz)\,\vec\jmath-3ye^x\sin(yz)\,\vec k

and

\vec a=-\vec\imath+2\,\vec\jmath+3\,\vec k\implies\|\vec a\|=\sqrt{(-1)^2+2^2+3^2}=\sqrt{14}

Then the derivative at p_0 in the direction of \vec a is

3\,\vec\imath\cdot\dfrac{-\vec\imath+2\,\vec\jmath+3\,\vec k}{\sqrt{14}}=-\dfrac3{\sqrt{14}}

3 0
3 years ago
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