Hey there!:
HCl + MnO2 → MnCl2 + H2O + Cl2
* in HCl the oxidation state of Cl is -1 .
* on the product side the oxidation state is 0 .
* therefore Cl gains electrons .
* in MnO2 the oxidation state of Mn is +4
* in MnCl2 the oxidation state of Mn is +2
Therefore Mn loses electrons
Answer A
Hope That helps!
The idea here is that you need to figure out how many moles of magnesium chloride,
MgCl
2
, you need to have in the target solution, then use this value to determine what volume of the stock solution would contain this many moles.
As you know, molarity is defined as the number of moles of solute, which in your case is magnesium chloride, divided by liters of solution.
c
=
n
V
So, how many moles of magnesium chloride must be present in the target solution?
c
=
n
V
⇒
n
=
c
⋅
V
n
=
0.158 M
⋅
250.0
⋅
10
−
3
L
=
0.0395 moles MgCl
2
Now determine what volume of the target solution would contain this many moles of magnesium chloride
c
=
n
V
⇒
V
=
n
c
V
=
0.0395
moles
3.15
moles
L
=
0.01254 L
Rounded to three sig figs and expressed in mililiters, the volume will be
V
=
12.5 mL
So, to prepare your target solution, use a
12.5-mL
sample of the stock solution and add enough water to make the volume of the total solution equal to
250.0 mL
.
This is equivalent to diluting the
12.5-mL
sample of the stock solution by a dilution factor of
20
.
Answer:
What is the net ionic equation for a reaction between HCl and NaOH?
Explanation:
A salt is a neutral ionic compound. Let's see how a neutralization reaction produces both water and a salt, using as an example the reaction between solutions of hydrochloric acid and sodium hydroxide. The overall equation for this reaction is: NaOH + HCl → H2O and NaCl
Hope that helped.
Answer:
Mass of water = 6251. 706g or 6.25Kg
Explanation:
Relative humidity = (actual vapor pressure/saturation vapor pressure) * 100%
Actual vapor pressure, Pw = relative humidity * saturation vapor pressure
Pw = 60% * (35.6 *0.001)atm = 0.0216atm
Note: 1mbar = 0.001atm
Using the ideal gas equation: PV=nRT; where P = Pw= 0.02136atm, V= (400
* 1000)dm^3, R= 0.082 atmdm^3/kmol, T= (27+273)K, n = number of moles
Note: 1m^3 = 1000dm^3,R is the molar gas constant.
Making n subject of the formula, n = PV/RT
n= (0.02136 * 400000)/(0.082 * 300) = 347.317 moles
Mass (g) = number of moles (n) * molar mass
molar mass of water=18g
Mass of water = 347.317 * 18 = 6251. 706g or 6.25Kg
Answer:
divide the distance by the average
Explanation:
ash QC ok
