J=1
explaination:
2 is greater than or equal to 3
4 - j(1)= 3
Answer:
See picture
Step-by-step explanation:
The rule is ...
![x^{m/n}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D)
The index of the surd becomes the denominator of the exponents inside.
This one.
The doubly-shaded area is the solution set. The dashed line is not included.
It’s negative by the looks of it.
If you solve it you get -2.5
I hope it’s correct!
Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
