a boy is enjoying a ride on giant wheel which is moving with a constant speed of 10 metre per second it implies a he is

Which geologic feature is most likely to form at a mid-ocean ridge: Peninsula, volcano, delta, or plateau?

Helga [31]

It is a volcano that is the answer.

7 0

3 years ago

To understand kinetic and static friction. A block of mass m lies on a horizontal table. The coefficient of static friction betw

frez [133]

Answer: a) Fmax= μs.m.g b) Ff=(μs.m.g /2 c) a= (μs.m.g - μk.m.g) / m

Explanation:

a) The friction force, is one of the components of the contact force, and can adopt any value to counteract an applied force, so the object doesn't move, till a maximum value, beyond which, if he applied force is larger, the object will start to move.

This limit value, is given by the following expression:

Fmax = μs. N = μs. m.g

(This is valid only if the contact surface is horizontal).

b) As explained above, if the applied force is smaller than the limit value, the friction force will adopt the same value as the applied force, but of opposite direction, so due to the Newton's 2nd Law, the object remains at rest.

In this case, if the push is horizontal, with a force equal to the half of the limit value, friction force will be exactly equal to half the maximum friction force, as follows:

Ff = (μs. m.g) / 2

c) As the applied force is equal to the static friction force, once in movement, the opposing friction force is equal to Ffk = μk. m.g (where μk ∠ μs).

So, if the applied force is larger than this friction force (that always oppose to the relative movement between both surfaces in contact each other), the object will suffer an acceleration, which value is obtained from the Newton's 2nd Law, as follows:

Ext F = m .a ⇒ a = (μs.m.g -μk. m.g ) / m

6 0

3 years ago

Read 2 more answers

A stone of 1 kg is thrown with a velocity of 40 m/s across the frozen surface of a lake and comes to rest after travelling a dis

yawa3891 [41]

Answer:

C)-16 N

Explanation:

concepts used

force = mass* acceleration

equation of motion

$v^2 = u^2 + 2as$

where v is the final velocity

u is the initial velocity

and s is the distance moved

______________________________________________

Given

mass = 1 kg

initial velocity (u) = 40m/s

final velocity (v) = 0 as stones comes to rest

distance moved by stone (s) = 50m

using $v^2 = u^2 + 2as$

$0 = 40^2 +2a*50\\=> -1600 = 100a\\=> a = -1600/100 = -16$

Thus, acceleration is -16 m/s^2

here acceleration is negative as force of friction is opposing the motion.

Force of friction = mass of stone * acceleration of stone

Force of friction = 1*-16 kgm/s^2 = -16N ( kgm/s^2 = 1 N)

Thus, option c -16N is correct choice.

4 0

3 years ago

Which subatomic particle identifies the element?

grin007 [14]

A. protons.ekgfsbdbsi

3 0

3 years ago

Read 2 more answers

Two equal, but oppositely charged particles are attracted to each other electrically. The size of the force of attraction is 48.

galina1969 [7]

Given:

The force of attraction is F = 48.1 N

The separation between the charges is

$\begin{gathered} r=\text{ 60.9 cm} \\ =\text{ 60.9}\times10^{-2}\text{ m} \end{gathered}$

Also, the magnitude of charge q1 = q2 = q.

To find the magnitude of charge.

Explanation:

The magnitude of charge can be calculated by the formula

$\begin{gathered} F=\frac{k(2q)}{r^2} \\ q=\frac{Fr^2}{2k} \end{gathered}$

Here, k is the Coulomb's constant whose value is

$k\text{ = 9}\times10^9\text{ N m}^2\text{ /C}^2$

On substituting the values, the magnitude of charge will be

$\begin{gathered} q=\frac{48.1\times(60.9^\times10^{-2})^2}{2\times9\times10^{^9}} \\ =9.91\times10^{-10}\text{ C} \\ =9.91\times10^{-4}\text{ }\mu C \end{gathered}$

Thus, the magnitude of each charge is 9.91 x 10^(-4) micro Coulombs.

6 0

2 years ago