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3 years ago

Help me answer correctly !!!! Will mark Brianliest !!!!!!!!!!!!!!!!

Mathematics

2 answers:

mrs_skeptik [129]3 years ago

6 0

Show the question so I can answer it for you.

netineya [11]3 years ago

5 0

Answer:

i will help honey if you ask me a question

Step-by-step explanation:

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Helppppp pleaseeeeeeeeeeeeeee

kirill115 [55]

We know that,

Sum of the angles in linear pair is 180°.

Given,

Angle 1 and Angle 2 are Linear Pair of Angles.

So,

Angle 1 + Angle 2 = 180°

=> 65° + Angle 2 = 180°

=> Angle 2 = 180° - 65°

=> Angle 2 = 115°

So, Angle 2 = 115°.

5 0

3 years ago

Read 2 more answers

what is 1.seven times the sum of x and y and 2.the product of two consecutive numbers when the smaller number is y

tresset_1 [31]

1. 7xy
2. y(y+1)

Hope this helps :)

7 0

3 years ago

The distance between two subway stations is 3 miles. If a train

dolphi86 [110]

Answer: 3

Step-by-step explanation:

Divide every mile is one minute

6 0

3 years ago

Look at the rectangle and the square: Ada says that the length of diagonal SQ is two times the length of diagonal OM. Is Ada cor

Musya8 [376]

Answer:

No, she is wrong.

Step-by-step explanation:

A diagonal of square or rectangle is equals to hypotenuse of a triangle. So you can apply Pythagoras Theorem to solve it :

${c}^{2} = {a}^{2} + {b}^{2}$

Rectangle,

${qs}^{2} = {rs}^{2} + {qr}^{2}$

${qs}^{2} = {16}^{2} + {8}^{2} = 320$

$qs = \sqrt{320} = 17.9 \: inches$

Square,

${om}^{2} = {lo}^{2} + {lm}^{2}$

${om}^{2} = {8}^{2} + {8}^{2} = 128$

$om = \sqrt{128} = 11.3 \: inches$

Given that QS is 17.9 and OM is 11.3. So SQ is not 2 times greater than OM.

$17.9 \div 11.3 = 1.58 \: (not \: equals \: to \: 2)$

7 0

3 years ago

The number of traffic violations in a city increased from 12 to 16 in a month. What is the percent of increase in the number of

Tems11 [23]

Answer:

33%

Step-by-step explanation:

Percentage increase = $\frac{increase}{initial value}$ x 100%

Number of traffic violations increased from 12 to 16.

Initial value = 12

Final value = 16

increase = Final value - Initial value

= 16 - 12

= 4

Percentage increase = $\frac{increase}{initial value}$ x 100%

= $\frac{4}{12}$ x 100%

= $\frac{1}{3}$ x 100%

= $\frac{100}{3}$ %

= 33.3333%

The percentage increase in the number of traffic violations for the month is 33%.

5 0

3 years ago