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Let x(t) = the length of a side of the square (cm) at time t (s).
The rate of change of x is given as
The area (cm²) at time t is
A = x²
The rate of change of the area with respect to time is
When A = 9 cm², then x = √9 = 3cm. Hence obtain
Answer: 12 cm²/s
The rate of change of x is given as
The area (cm²) at time t is
A = x²
The rate of change of the area with respect to time is
When A = 9 cm², then x = √9 = 3cm. Hence obtain
Answer: 12 cm²/s
Given values of EB and ED are
And from the diagram, we can say that D is the midpoint of EB.
THerefore
Substituting the values of EB and ED, we will get
Therefore,