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Mandarinka [93]
3 years ago
8

How how would scientist describe a sunset

Physics
1 answer:
Scilla [17]3 years ago
3 0

a creamy texture of orange  ,yellow ,pink, red,and purple. Because it is when the sun is goinig down and the sun reflects on stuff which makes it the colors it does for a sun set
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The maximum amount of pulling force a truck can apply when driving on
kupik [55]
C the correct but not sure?
5 0
3 years ago
Do you have a lawn mower engine running for 20 minutes does 4,560, 000 J of work. What is the power output of the engine?
alekssr [168]

Answer:

P = 3800 W

Explanation:

Power is equal to energy divide by time P = E/t

plug in 4560000 J for energy

convert 20 minutes to seconds

20 * 60 = 1200 seconds

plug in 1200 seconds for time

P = 4560000/1200

P = 3800 W

7 0
3 years ago
What is the reflectivity of a glass surface (n =1.5) in air (n = 1) at an 45° for (a) S-polarized light and (b) P-polarized ligh
Goshia [24]

Answer:

a) R_s = 0.092

b) R_p = 0.085

Explanation:

given,

n =1.5 for glass surface

n = 1 for air

incidence angle = 45°

using Fresnel equation of reflectivity of S and P polarized light

R_s=\left | \dfrac{n_1cos\theta_i-n_2cos\theta_t}{n_1cos\theta_i+n_2cos\theta_t} \right |^2\\R_p=\left | \dfrac{n_1cos\theta_t-n_2cos\theta_i}{n_1cos\theta_t+n_2cos\theta_i} \right |^2

using snell's law to calculate θ t

sin \theta_t = \dfrac{n_1sin\theta_i}{n_2}=\dfrac{sin45^0}{1.5}=\dfrac{\sqrt{2}}{3}

cos \theta_t =\sqrt{1-sin^2\theta_t} = \dfrac{sqrt{7}}{3}

a) R_s=\left | \dfrac{\dfrac{1}{\sqrt{2}}-\dfrac{1.5\sqrt{7}}{3}}{\dfrac{1}{\sqrt{2}}+\dfrac{1.5\sqrt{7}}{3}} \right |^2

R_s = 0.092

b) R_p=\left | \dfrac{\dfrac{\sqrt{7}}{3}-\dfrac{1.5}{\sqrt{2}}}{\dfrac{\sqrt{7}}{3}+\dfrac{1.5}{\sqrt{2}}} \right |^2

R_p = 0.085

3 0
3 years ago
Where can classic examples of shield volcanoes be found?
Darina [25.2K]
The largest is Mauna Loa on the Big Island of Hawaii; all the volcanoes in the Hawaiian Islands are shield volcanoes. There are also shield volcanoes, for example, in Washington, Oregon, and the Galapagos Islands
4 0
3 years ago
A flatbed truck is supported by its four drive wheels, and is moving with an acceleration of 6.3 m/s2. For what value of the coe
Levart [38]

Answer:

Coefficient of static friction will be equal to 0.642  

Explanation:

We have given acceleration a=6.3m/sec^2

Acceleration due to gravity g=9.8m/sec^2

We have to find the coefficient of static friction between truck and a cabinet will

We know that acceleration is equal to a=\mu g, here \mu is coefficient of static friction and g is acceleration due to gravity

So \mu =\frac{a}{g}=\frac{6.3}{9.8}=0.642

So coefficient of static friction will be equal to 0.642

3 0
3 years ago
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