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4 years ago

How are the layers of the atmosphere separated

Physics

2 answers:

Volgvan4 years ago

8 0

Answer:

it depends on temperature^^

Explanation:

hope this helped^^

Makovka662 [10]4 years ago

4 0

Answer:

The atmosphere can be divided into layers based on its temperature, as shown in the figure below. These layers are the troposphere, the stratosphere, the mesosphere and the thermosphere. A further region, beginning about 500 km above the Earth's surface, is called the exosphere.

Explanation:

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Constanza is on a commuter train between Richville and Shoptown. The train takes 35 minutes to cover the distance between the tw

just olya [345]

Answer:

1.) Displacement = 32.08m

2.) Velocity = 55km/h

3.) Acceleration = 94.29 km/h^2

Explanation:

Given that the train takes 35 minutes to cover the distance between the two towns. The train's average speed is 55 kilometers per hour. That is,

Time t = 35 minute

Convert it to hours by dividing it by 60

35/60 = 7/12 hours

Speed = 55 km/h

The displacement of the car is:

Displacement = 55 × 7/12 = 32.08 m

The velocity of the car will be 55 km/h

The acceleration of the car will be:

Acceleration = velocity/time

Substitute velocity and time into the formula

Acceleration = 55 ÷ 7/12

Acceleration = 94.29 km/h^2

5 0

4 years ago

A stone is dropped at t = 0. A second stone, with twice the mass of the first, is dropped from the same point at t = 181 ms. How

lara [203]

Answer:

the center of mass is 316,670m bellow the release point.

Explanation:

First, we must find the distance at which the objects are in time t = 360s

We will use the formula for vertical distance in free fall

$h=v_{0}t+\frac{1}{2} gt^2$

$v_{0}$ is the initial velocity, is 0 for both stones since they were just dropped.

g is acceleration of gravity and t is time ( $g=9.81m/s^2$ )

At $t=360s$ the first stone has been falling for the entire 360 seconds, its position h1 is:

$h_{1}=\frac{1}{2} (9.82m/s^2)(360s^2)=635,688m$

And at 360 seconds the second stone has been fallin for $t= 360s -181 s = 179s$ , so its position h2 is:

$h_{2}=\frac{1}{2} (9.81m/s^2)(179)^2=157,161.1m$

And finally using the equation for the center of mass:

$CM=\frac{m_{1}h_{1}+m_{2}h_{2}}{m_{1}+m_{2}}$

We know that the mass of the second stone is twice the mass of the first stone so:

$m_{1}=m\\m_{2}=2m$

replacing these values in the equation for the center of mass

$CM=\frac{mh_{1}+2mh_{2}}{m+2m}$

$CM=\frac{m(h_{1}+2h_{2})}{3m}=\frac{h_{1}+2h_{2}}{3}$

Finally, replacing the values we found fot h1 and h2:

$CM=\frac{635,688m+2(157,161.1m)}{3}=316,670m$

the center of mass is 316,670m bellow the release point.

8 0

4 years ago

A lens is designed to work in the visible, near-infrared, and near-ultraviolet. The best resolution of this lens from a diffract

Anestetic [448]

In the near ultraviolet

8 0

3 years ago

Calculate the total mass of these letters in grams (mxe=131.29amu)

Lady_Fox [76]

We know avogadro's number = 6.023 x 10²³
1 amu = 1 atomic mass unit = 1/ (6.023 x 10²³) gm = 1.66 x 10⁻²⁴grams
Now, to convert amu to grams,
131.29 amu = 131.29 x 1.66 x 10⁻²⁴grams
= 2.18 x 10⁻²² grams is the answer

4 0

4 years ago

Read 2 more answers

What kind of education is required to be a ocean engineer?

ra1l [238]

To become an ocean engineer, the job would require a Bachelors degree in ocean engineering.

Hope this helps.

4 0

4 years ago