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yarga [219]
2 years ago
8

A 70mm long blockhas cross-section of 50mm by 10mm the block is subjected to forces 60KN (tension) on the 50mm by 10mm face and

110KN (Compression) on the 70mm by 10mm face Determine the force to be applied on the 70mm by 50mm face such that there is no change in volume
Physics
1 answer:
sammy [17]2 years ago
7 0

Answer:

970 kN

Explanation:

The length of the block = 70 mm

The cross section of the block = 50 mm by 10 mm

The tension force applies to the 50 mm by 10 mm face, F₁ = 60 kN

The compression force applied to the 70 mm by 10 mm face, F₂ = 110 kN

By volumetric stress, we have that for there to be no change in volume, the total pressure applied by the given applied forces should be equal to the pressure removed by the added applied force

The pressure due to the force F₁ = 60 kN/(50 mm × 10 mm) = 120 MPa

The pressure due to the force F₂ = 110 kN/(70 mm × 10 mm) = 157.142857 MPa

The total pressure applied to the block, P = 120 MPa + 157.142857 MPa = 277.142857 MPa

The required force, F₃ = 277.142857 MPa × (70 mm × 50 mm) = 970 kN

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The angle between any two vectors can be found by scalar product of them:

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\vec{v}(t).\vec{a}(t) = |\vec{v}(t)|.|\vec{a}(t)|.\cos(\theta)\\36t = \sqrt{4 + 7 + 36t^2}.6.\cos(\theta)

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Read 2 more answers
How is Coulomb’s law similar to newton’s law of gravitational force? How is it different
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The similarities and the differences between gravitational and electric force are listed below

Explanation:

- The magnitude of the gravitational force between two objects is given by Newton's law of gravitation:

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between them

- Coloumb's law gives instead the strength of the electrostatic force between two charged objects, which is

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

By comparing the two equations, we find the following similarities:

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  • Both the forces are proportional to the product between the "main quantity" of each force, which is the mass for the gravitational force (F\propto m_1 m_2) and the charge for the electric force (F\propto q_1 q_2

Instead, we have the following differences:

  • The gravitational force is always attractive, since the sign of m is always positive, while the electric force can be either attractive or repulsive, since the sign of q can be either positive or negative
  • The value of the gravitational costant G is much smaller than the value of the Coulomb's constant, so the gravitational force is much weaker than the electric force

Learn more about gravitational force and electric force:

brainly.com/question/1724648

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brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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