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Serjik [45]
3 years ago
11

A boy pulls with a 92.5 N force on the handle of a 27.5 kg wagon while the handle makes an angle of 35.0 degrees with the horizo

ntal. If friction is negligible, and the boy pulls a total distance of 215.6 m, how much work has the boy done
Physics
1 answer:
sweet [91]3 years ago
8 0

Answer:

W_b \approx 16336J

Explanation:

From the question we are told that

Force of pull F= 92.5

Weight of handle W_h=27.5 kg

Angle of handle \angle =35.0

Distance d=215.6 m

Generally the work done by the boy can mathematically be represented as

W_b=F*dcos \theta

W_b=92.5*27.5 *cos(35)

Therefore

W_b=16336.34922J

W_b \approx 16336J

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anzhelika [568]

Answer:

aₓ = 0 ,       ay = -6.8125 m / s²

Explanation:

This is an exercise that we can solve with kinematics equations.

Initially the rabbit moves on the x axis with a speed of 1.10 m / s and after seeing the predator acceleration on the y axis, therefore its speed on the x axis remains constant.

x axis

          vₓ = v₀ₓ = 1.10 m / s

          aₓ = 0

y axis

initially it has no speed, so v₀_y = 0 and when I see the predator it accelerates, until it reaches the speed of 10.6 m / s in a time of t = 1.60 s. let's calculate the acceleration

         v_{y}= v_{oy} -ay t

          ay = (v_{oy} -v_{y}) / t

          ay = (0 -10.9) / 1.6

          ay = -6.8125 m / s²

the sign indicates that the acceleration goes in the negative direction of the y axis

8 0
3 years ago
How much heat is released when 30 g of water at 96°C cools to 25°C?The specific heat of water is 1 cal/gºC.
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Answer:

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Explanation:

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Okay, haven't done physics in years, let's see if I remember this.

So Coulomb's Law states that F = k \frac{Q_1Q_2}{d^2} so if we double the charge on Q_1 and double the distance to (2d) we plug these into the equation to find

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So we see the new force is exactly 1/2 of the old force so your answer should be \frac{1}{2}F if I can remember my physics correctly.

8 0
3 years ago
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