Ask question

Ask question

All categories

3 years ago

11

A boy pulls with a 92.5 N force on the handle of a 27.5 kg wagon while the handle makes an angle of 35.0 degrees with the horizo

ntal. If friction is negligible, and the boy pulls a total distance of 215.6 m, how much work has the boy done

1 answer:

sweet [91]3 years ago

8 0

Answer:

$W_b \approx 16336J$

Explanation:

From the question we are told that

Force of pull $F= 92.5$

Weight of handle $W_h=27.5 kg$

Angle of handle $\angle =35.0$

Distance $d=215.6 m$

Generally the work done by the boy can mathematically be represented as

$W_b=F*dcos \theta$

$W_b=92.5*27.5 *cos(35)$

Therefore

$W_b=16336.34922J$

$W_b \approx 16336J$

You might be interested in

The tidal lung volume of human breathing, representing the amount of air inhaled and exhaled in a normal breath, is 500 cm3. (As

Darina [25.2K]

Answer:

Explanation:

Temperature of air = 18°C = 273 + 18 = 291 K .

volume = 500 cc = 0 .5 litre .

pressure = one atmosphere ( atm) .

From gas equation , we can calculate this volume at NTP as follows.

volume = .5 x ( 273 / 291 ) litre

= 0.469 litre .

In any gas at NTP , 22.4 litre contains 6.02 x 10²³ molecules

.469 litre will contain 6.02 x 10²³ x .469 / 22.4 molecules

= 126 x 10²⁰ molecules .

b )

one mole = 6.02 x 10²³ molecules

6.02 x 10²³ molecules has weight of 28.96 grams

126 x 10²⁰ molecules has weight of 28.96 x 126 x 10²⁰ / 6.02 x 10²³ grams

= .606 gram .

c )

volume of all the air in the atmosphere = volume of sphere

= 4 / 3 x π x R³

= ( 4 / 3) x 3.14 x (999.5 x 10³ )³ m³

= 4.18 x 10¹⁸ m³

density of air = 1.225 kg / m³

mass of air = 1.225 x 4.18 x 10¹⁸ kg

= 5.12 x 10¹⁸ kg

d )

volume of air inhaled by 7 billion people

= . 5 x 7 x 10⁹ litre

= 3.5 x 10⁶ m³ .

Total volume of air in atmosphere = 4.18 x 10¹⁸ m³

required percentage

= 3.5 x 10⁶ x 100 / 4.18 x 10¹⁸

= .8373 x 10⁻¹⁰ % .

6 0

3 years ago

Planet Tatoone is about 1.7 AU from its Sun. Approximately how long will it take for light to travel from the Sun to Tatoone in

Radda [10]

Answer:

The value is $t = 14.129 \ minutes$

Explanation:

From the question we are told that

The distance of planet Tatoone is $d = 1.7 \ AU = 1.7 *1.496* 10^{11}=2.543*10^{11} \ m$

The speed of light is $c = 3.0*10^{8} \ m/ s$

Generally the time taken is mathematically represented as

$t = \frac{d}{c}$

=> $t = \frac{2.543*10^{11}}{3.0*10^{8} }$

=> $t = 847.7 \ s$

Now converting to minutes

$t = \frac{847.7}{60}$

=> $t = 14.129 \ minutes$

8 0

3 years ago

A wave travelling along the positive x-axis side with a

andrew11 [14]

Explanation:

The frequency is given to be f = 8 Hz.

Period is the inverse of frequency.

T = 1/f = 0.125 s

Velocity is wavelength times frequency.

v = λf = (0.40 m) (8 Hz) = 3.2 m/s

The wave travels 3.2 meters every second.

5 0

3 years ago

Relation between wavelength wave velocity and time period

Snezhnost [94]

Answer: wavelength=velocity×period

Explanation:the relation between velocity, wavelength and period is

Wavelength=velocity×period

8 0

2 years ago

The logarithm of x, written log(x), tells you the power to which you would raise 10 to get x. So, if y=log(x), then x=10^y. It i

fomenos

To solve this problem it is necessary to apply the rules and concepts related to logarithmic operations.

From the definition of logarithm we know that,

$Log_{10}(10) = 1$

In this way for the given example we have that a logarithm with base 10 expressed in the problem can be represented as,

$log_{10}(1,000,000)$

We can express this also as,

$log_{10}(10^6)$

By properties of the logarithms we know that the logarithm of a power of a number is equal to the product between the exponent of the power and the logarithm of the number.

So this can be expressed as

$6*log_{10}(10)$

Since the definition of the base logarithm 10 of 10 is equal to 1 then

$6*1=6$

The value of the given logarithm is equal to 6

8 0

3 years ago