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Genrish500 [490]
2 years ago
13

An orchestra of 25 members bought tickets, at all different prices, to a concert, and the mean price paid was $82. A new musicia

n joined the orchestra and spent $90 on his ticket to the same concert. What is the new mean price paid when the new musician is included? Round to the nearest cent.
Mathematics
1 answer:
QveST [7]2 years ago
4 0

Answer:

$82.31

Step-by-step explanation:

First, we need to find the total amount of money paid

82 * 25 = 2050\\

Next, add the new price for the new total

2050 + 90 = 2160

Now divide by total members (25 +1 = 26)

2160 / 90 = $82.31

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2, 5, 9, 14, ?, 27. what’s the missing number?
poizon [28]

Answer:

20

Step-by-step explanation:

2, 5, 9, 14, ?, 27.

2,5 the number added is 3

5,9 the number added is 4

9,14 the number added is 5

14,20 the number added is 6

20 , 27 the number added is 7

7 0
3 years ago
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. The formula for the area A of a trapezoid is
cupoosta [38]

Answer:

h=A/(b1+b2/2)

Step-by-step explanation:

it is the reverse

8 0
3 years ago
Can someone Evaluate 2(4-1)^2
SIZIF [17.4K]

Answer:

The answer is 36

Step-by-step explanation:

First solve in parenthesis; 4-1=3

Then multiply that by the 2 to get 6

Then raise that value by the square root of 6^2 = 36

5 0
3 years ago
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What is the value of the digit 4 in 46000?
IgorC [24]
I think it is the tens because the first is ten thousand, second is thousand, third is hundreds and last is units ones
4 0
3 years ago
Read 2 more answers
I’m confused on this one
dedylja [7]

It's a parallelogram so if one angle is 90 degrees they all will be because of transverse angles and all that good stuff.


So we're given the diagonal of a rectangle and one side and we're asked to find the other. The diagonal of a rectangle is the hypotenuse of the right triangle whose legs are the sides of the rectangle. So this is a Pythagorean Theorem question in disguise:


AB^2 + AD^2 = BD^2


AD^2 = BD^2 - AB^2


AD = \sqrt{ BD^2 - AB^2 }


AD = \sqrt{149^2 - 51^2} = \sqrt{19400} = 140


Answer: 140 cm


I don't recall seeing this Pythagorean Triple before.





3 0
3 years ago
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