Part 1:
For this case we must see in the graph the axis of symmetry of the given parabola.
We have then that the axis of symmetry is the vertical line t = 2.
Answer:
The height of the javelin above the ground is symmetric about the line t = 2 seconds:
Part 2:
For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time.
We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph.
Then, we must observe the moment when it returns to be 20 feet above the ground.
For this, observing the graph we see that:
h (3) = 20 feet
Therefore, a height of 20 feet is again reached in 3 seconds.
Answer:
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
Answer:
The answer would be the third option, segment AS
4.0833 sorry if i’m wrong luv did you want it in a fraction?
Answer:
A. 12+2p
G. p+p+12
Step-by-step explanation:
The Eagles basketball team scored 12 more than 2 times as many points in the last game of the season than in the first game
Number of points scored in the last game of the season = 2p + 12
A. 12+2p
Equivalent
B. 2+p+12
= P + 14
Not equivalent
C. 2+12p
Not equivalent
D. p(2+12)
= 2p + 12p
Not equivalent
E. p+2+12
= P + 14
Not equivalent
F. 12p+2p
Not equivalent
G. p+p+12
= 2p + 12
Equivalent
