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puteri [66]
2 years ago
7

Why is it impossible for a solution to become both more basic and more acidic at the same time?

Chemistry
2 answers:
Ganezh [65]2 years ago
6 0

A solution cannot be both acidic and basic at the same time because an increase in the H+ concentration will lead to a decrease in OH- concentration in the same solution.

<h3>What is pH?</h3>

pH is the degree of acidity or alkalinity of a solution.

pH = -log [H+]

Also

pOH = -log [OH-]

Mathematically, pH + pOH = 14

Thus, for a given solution, as the pH increases, pOH decreases, and vice versa.

More on pH can be found here: brainly.com/question/491373

elena55 [62]2 years ago
4 0

An increase in H+ concentration will decrease OH- concentration is the

reason why it's impossible.

<h3>What is an Acidic and Basic compound?</h3>

An acidic compound has the presence of H+ ions in them while basic

compounds have the presence of OH- ions.

In a solution , as the number of Hydrogen ions increases, it leds to a

corresponding decrease in the Hydroxide ions which is the reason why

they can't coexist at the same time.

Read more about Acidic and basic compounds here brainly.com/question/4046668

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3 years ago
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Elenna [48]

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3 years ago
The acid dissociation constant Ka of boric acid (H3BO3) is 5.8 times 10^-10. Calculate the pH of a 4.4 M solution of boric acid.
madam [21]

Answer: The pH of a 4.4 M solution of boric acid is 4.3

Explanation:

H_3BO_3\rightarrow H^+H_2BO_3^-

at t=0  cM              0             0

at eqm c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 4.4 M and \alpha = ?

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Putting in the values we get:

5.8\times 10^{-10}=\frac{(4.4\times \alpha)^2}{(4.4-4.4\times \alpha)}

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[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M

Also pH=-log[H^+]

pH=-log[4.8\times 10^{-5}]=4.3

Thus pH of a 4.4 M H_3BO_3 solution is 4.3

3 0
3 years ago
Which compound are ionic and which are covalent? (N2) (CCl4) (SiO2) (AlCl3) (CaCl2) (LiBr)
muminat
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Ionic compounds: CaCl2 and LiBr.

Hope this helps!
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