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kati45 [8]
3 years ago
14

3. What was your average percent error for all three trials? In this experiment you did three trials. Why was it suggested that

you do three trials and not fewer?
Chemistry
2 answers:
sweet [91]3 years ago
7 0

Answer:

To be sure of the value you will obtain

Explanation:

Trial 1

Mass of calorimeter: 409g

Temp of calorimeter: 20Cº

Mass of calorimeter + water: 457g

Temp of calorimeter + water: 20Cº

Mass of calorimeter + water + ice: 510g

Temp of calorimeter + water + ice: –

Mass of calorimeter + ice: 450g

Temp of calorimeter + ice: 0Cº

Trial 2

Mass of calorimeter: 409g

Temp of calorimeter: 20Cº

Mass of calorimeter + water: 461g

Temp of calorimeter + water: 22Cº

Mass of calorimeter + water + ice: 515g

Temp of calorimeter + water + ice: –

Mass of calorimeter + ice: 447g

Temp of calorimeter + ice: 0Cº

Trial 3

Mass of calorimeter: 409g

Temp of calorimeter: 20Cº

Mass of calorimeter + water: 459g

Temp of calorimeter + water: 22Cº

Mass of calorimeter + water + ice: 513g

Temp of calorimeter + water + ice: –

Mass of calorimeter + ice: 448g

Temp of calorimeter + ice: 0Cº

stira [4]3 years ago
6 0

To be sure of the value you will obtain

Explanation:

Trial 1Mass of calorimeter: 409gTemp of calorimeter: 20CºMass of calorimeter + water: 457gTemp of calorimeter + water: 20CºMass of calorimeter + water + ice: 510gTemp of calorimeter + water + ice: –Mass of calorimeter + ice: 450gTemp of calorimeter + ice: 0Cº

Trial 2Mass of calorimeter: 409gTemp of calorimeter: 20CºMass of calorimeter + water: 461gTemp of calorimeter + water: 22CºMass of calorimeter + water + ice: 515gTemp of calorimeter + water + ice: –Mass of calorimeter + ice: 447gTemp of calorimeter + ice: 0Cº

Trial 3Mass of calorimeter: 409gTemp of calorimeter: 20CºMass of calorimeter + water: 459gTemp of calorimeter + water: 22CºMass of calorimeter + water + ice: 513gTemp of calorimeter + water + ice: –Mass of calorimeter + ice: 448gTemp of calorimeter + ice: 0Cº

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Which of the following is NOT a characteristic of metals?
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PLEASE SOMEONE! The density of the acetic acid solution is 1.05 g/mL. Calculate the %(m/m) of the acetic acid solution (convert
tigry1 [53]

Answer:

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Explanation:

Density of acetic acid solution = 1.05 g/mL

Volume of acetic acid solution = 0.1 L = 100 mL

From the formula, Density = mass / volume; mass = density × volume

Mass of acetic acid solution = 1.05 g/mL × 100 mL = 105 g

Molar concentration of acetic acid solution = 0.243 mol/L

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From the formula, mass concentration = molar concentration × molar mass

Mass concentration of acetic acid, CH₃COOH = 0.243 mol/L × 60 g/mol = 14.58 g/L

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The diagram shows the box for an element in the periodic
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Explanation: hope this helps!

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The AE of a system that releases 12.4 J of heat and does 4.2 J of work on its surroundings It is_______ jA. 16.6 B. 12.4 C. 4.2
andre [41]

ANSWER

EXPLANATION

Given that

The energy released by the system is 12.4J

Work done on the surrounding is 4.2J

Follow the steps below to find the change in energy

In the given data, energy is said to be released to the surroundings

Recall, that exothermic reaction is a type of reaction in which heat is released to the surroundings. Hence, change in enthalpy is negative

Step 1; Write the formula for calculating change in energy

\Delta E\text{ }=\text{ q }+\text{ w}

Since heat is released to the surrounding, then q = -12J

Recall, that work done by the system on the surroundings is always negative

Hence, w = -4.2J

Step 2; Substitute the given data into the formula in step 1

\begin{gathered} \text{  }\Delta E\text{ = q + w} \\ \text{  }\Delta E\text{ }=\text{ -12.4 }+\text{ \lparen-4.2\rparen} \\ \text{  }\Delta E\text{ = -12.4 - 4.2} \\ \text{  }\Delta E\text{ }=\text{ -16.6J} \end{gathered}

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