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kati45 [8]
4 years ago
14

3. What was your average percent error for all three trials? In this experiment you did three trials. Why was it suggested that

you do three trials and not fewer?
Chemistry
2 answers:
sweet [91]4 years ago
7 0

Answer:

To be sure of the value you will obtain

Explanation:

Trial 1

Mass of calorimeter: 409g

Temp of calorimeter: 20Cº

Mass of calorimeter + water: 457g

Temp of calorimeter + water: 20Cº

Mass of calorimeter + water + ice: 510g

Temp of calorimeter + water + ice: –

Mass of calorimeter + ice: 450g

Temp of calorimeter + ice: 0Cº

Trial 2

Mass of calorimeter: 409g

Temp of calorimeter: 20Cº

Mass of calorimeter + water: 461g

Temp of calorimeter + water: 22Cº

Mass of calorimeter + water + ice: 515g

Temp of calorimeter + water + ice: –

Mass of calorimeter + ice: 447g

Temp of calorimeter + ice: 0Cº

Trial 3

Mass of calorimeter: 409g

Temp of calorimeter: 20Cº

Mass of calorimeter + water: 459g

Temp of calorimeter + water: 22Cº

Mass of calorimeter + water + ice: 513g

Temp of calorimeter + water + ice: –

Mass of calorimeter + ice: 448g

Temp of calorimeter + ice: 0Cº

stira [4]4 years ago
6 0

To be sure of the value you will obtain

Explanation:

Trial 1Mass of calorimeter: 409gTemp of calorimeter: 20CºMass of calorimeter + water: 457gTemp of calorimeter + water: 20CºMass of calorimeter + water + ice: 510gTemp of calorimeter + water + ice: –Mass of calorimeter + ice: 450gTemp of calorimeter + ice: 0Cº

Trial 2Mass of calorimeter: 409gTemp of calorimeter: 20CºMass of calorimeter + water: 461gTemp of calorimeter + water: 22CºMass of calorimeter + water + ice: 515gTemp of calorimeter + water + ice: –Mass of calorimeter + ice: 447gTemp of calorimeter + ice: 0Cº

Trial 3Mass of calorimeter: 409gTemp of calorimeter: 20CºMass of calorimeter + water: 459gTemp of calorimeter + water: 22CºMass of calorimeter + water + ice: 513gTemp of calorimeter + water + ice: –Mass of calorimeter + ice: 448gTemp of calorimeter + ice: 0Cº

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Which of the following statements is true about rain falling from clouds?*
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Write the molecular formula in the of the following compounds.
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How many molecules of propane were in the erlenmeyer flask? Avogadro's number is 6. 022 × 10^23 molecules/mol
Ede4ka [16]

3.74×10^{21}

3.74 ×10^{21} molecules of propane were in the erlenmeyer flask.

number of moles of propane can be calculated as moles of propane.

mass of propane =  0.274 g

molar mass of propane = 44.1

So this gives us the value of 6.21×10^{-3} moles of propane

No one mole of propane As a 6.0-2 × 10^{23}

so, 6.21 ×10^{-3} × 6. 022 × 10^23

= 3.74 ×10^{21}

Therefore, molecules of propane were in the erlenmeyer flask is found to be 3.74 ×10^{21}

<h3>What is erlenmeyer flask?</h3>
  • A laboratory flask with a flat bottom, a conical body, and a cylindrical neck is known as an Erlenmeyer flask, sometimes known as a conical flask or a titration flask.
  • It bears the name Emil Erlenmeyer after the German chemist.

<h3>What purpose does an Erlenmeyer flask serve?</h3>
  • Liquids are contained in Erlenmeyer flasks, which are also used for mixing, heating, chilling, incubating, filtering, storing, and other liquid-handling procedures.
  • For titrations and boiling liquids, their sloped sides and small necks make it possible to whirl the contents without worrying about spills.

To learn more about calculating total molecules visit:

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