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2 years ago

HEY EVERYONE its poofett my account got deleted for no absolute reason! >:D

Chemistry

2 answers:

PilotLPTM [1.2K]2 years ago

5 0

Answer:

am very sorry

Explanation:

marshall27 [118]2 years ago

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Sorry, someone must have repeatedly reported your account

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The [OH-] of a solution is 7.89 10^-12 M. What is the pH of the solution? it acidic or basic? *

kompoz [17]

Answer: pH = 2,897 , basic $[H+][OH-] = 10^{-14} ==> [H+] = \frac{10^{-14}}{7,89*10^{-12} } =\frac{1}{789} \\pH= -lg([H+]) = 2,897 \\pH basic$

Explanation:

6 0

3 years ago

You make an experiment to determine the percent mass of carbon in sugar. You find out that there is 46.63g of carbon in 75.00g o

Aleksandr [31]

Taking into account the definition of percentage composition, the percent composition of carbon in this sample is 62.17%.

<h3>Percentage composition</h3>

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

Then, the percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

$percentageby mass= \frac{mass of solute}{mass of solution}x100$

In this case, you know:

mass of solute= 46.63 g
mass of solution= 75 g

Replacing:

$percentageby mass= \frac{46.63 g}{75 g}x100$

Solving:

<u><em>percentage by mass= 62.17 %</em></u>

Finally, the percent composition of carbon in this sample is 62.17%.

Learn more about percent composition:

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3 0

2 years ago

How many moles of Au atoms are present in one ounce of pure gold? [1 oz = 28.4 g]

IgorLugansk [536]

Answer:

3.36x10^27 atoms

3 0

3 years ago

Is Calcium oxide (CaO) covalent or ionic?

Paul [167]

Answer:

Calcium oxide （CaO）is ionic.

6 0

3 years ago

Read 2 more answers

4) Balance the following redox reaction in an acidic solution. What are the coefficients in front of H⁺ and Fe3+ in the balanced

Kryger [21]

Answer:

- The coefficients in front of H⁺ and Fe³⁺ are 8 and 5

- There are transferred 5 moles of e-

Explanation:

This is the reaction:

Fe²⁺(aq) + MnO₄⁻(aq) → Fe³⁺(aq) + Mn²⁺(aq)

Let's think the oxidation numbers:

Fe2+ changed to Fe3+

It has increased the oxidation number → OXIDATION

Mn in MnO₄⁻ acts with +7 and it changed to Mn²⁺

It has decreased the oxidation number → REDUCTION

Let's make the half reactions:

Fe²⁺ → Fe³⁺ + 1e⁻ (it has lost 1 mol of e⁻)

MnO₄⁻ + 5e⁻ → Mn²⁺ (it has gained 5 mol of e⁻)

Now we have to ballance the O. In acidic medium we complete with water as many oxygens we have, in the opposite side. We have 4 O in reactant side, so we fill up with 4 H2O in products side.

MnO₄⁻ + 5e⁻ → Mn²⁺ + 4H₂O

Now we have to ballance the H, so as we have 8 H in products side, we complete with 8H⁺ in reactants, this is the complete half reaction:

8H⁺ + MnO₄⁻ + 5e⁻ → Mn²⁺ + 4H₂O

Notice that have 1e⁻ in oxidation and 5e⁻ in reduction. We must multiply (x5) the half reaction of oxidation, so the electrons can be cancelled.

(Fe²⁺ → Fe³⁺ + 1e⁻ ) .5

5Fe²⁺ → 5Fe³⁺ + 5e⁻

8H⁺ + MnO₄⁻ + 5e⁻ → Mn²⁺ + 4H₂O

We sum both half reactions:

5Fe²⁺ + 8H⁺ + MnO₄⁻ + 5e⁻ → 5Fe³⁺ + 5e⁻ + Mn²⁺ + 4H₂O

The electrons are cancelled, so the ballanced reaction is this:

5Fe²⁺ + 8H⁺ + MnO₄⁻ → 5Fe³⁺ + Mn²⁺ + 4H₂O

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3 years ago

HEY EVERYONE its poofett my account got deleted for no absolute reason! >:D​

HEY EVERYONE its poofett my account got deleted for no absolute reason! >:D