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Ostrovityanka [42]
3 years ago
13

How many grams of \text{NaCl}NaClstart text, N, a, C, l, end text will be produced from 18.0 \text{ g}18.0 g18, point, 0, start

text, space, g, end text of \text{Na}Nastart text, N, a, end text and 23.0 \text{ g}23.0 g23, point, 0, start text, space, g, end text of \text{Cl}_2Cl
2

​

start text, C, l, end text, start subscript, 2, end subscript?
Chemistry
1 answer:
Nezavi [6.7K]3 years ago
3 0

Answer:

18.7887 g of NaCl

Explanation:

<em>The question reads - How many grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2?</em>

Let us start by writing out the balanced equation of the reaction:

Na + Cl2 ---> NaCl2

1 mole, each of Na and Cl2 is required to produce 1 mole of NaCl.

mole = mass/molar mass

Therefore

18 g of Na = 18/23 = 0.7826 mole

23 g of Cl2 = 23/71 = 0.3239 mole

In this case, the Na is in excess and the Cl2 becomes the limiting reagent. Hence

0.3239 mole of Cl2 will react with 0.3239 mole of Na to yield 0.3239 mole of NaCl.

mass of 0.3239 mole NaCl = 0.3239 x 58 = 18.7887 g

<u>Hence, 18.7887  grams of NaCl will be produced from 18.0 g of Na and 23.0 g of Cl2.</u>

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The balanced chemical reaction for the synthesis of silver chloride has been:

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From the balanced equation, since there has presence equal moles of silver nitrate and sodium chloride, the moles of silver chloride formed has been equivalent. Thus, 1 mole of silver nitrate gives 1 mole of silver chloride.

The moles of silver nitrate available are,  \rm M_A_g_N_O_3=15\;mol

The moles of silver nitrate produced can be given as:

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For more information about moles produced, refer to the link:

brainly.com/question/10606802

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