Answer:
162.35 amu
Explanation:
Let A represent isotope X-159
Let B represent isotope X-163
Let C represent isotope X-164
The following data were obtained from the question:
Isotope >>> Abundance >>> Mass no
A >>>>>>>> 30.60 >>>>>>>> 159.37
B >>>>>>>> 15.79 >>>>>>>>> 162.79
C >>>>>>>> 53.61 >>>>>>>>> 163.92
Average Atomic mass =.?
The average atomic mass of element X can be obtained as follow:
Average atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100] + [(mass of C × C%)/100]
= [(159.37 × 30.60)/100] + [(162.79 × 15.79)/100] + [(163.92 × 53.61)/100]
= 48.77 + 25.70 + 87.88
= 162.35 amu
Therefore, the average atomic mass of element X is 162.35 amu
Yep u right bro but like you know I’m here with these guys you know what I mean tho
Volatile organic compounds are compounds
that easily evaporate at standard room temperature and pressure. They are
considered harmful to the environment if regulations are not followed. Examples
of this are:
Benzene
Ethanol
Benzopyrene
Ethenone
Acetic acid
Methane
Butane
Heptane
Pentane
Explanation:
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