A. The greatest height reached by the ball is 15.876 m
B. The ball left the kicker's foot with a speed of 17.64 m/s
To solve the question given above, we begin by calculating the time taken for the ball to get to the greatest height. This can be obtained as follow:
Time of flight (T) = 3.6 s
<h3>Time taken to reach the greatest height (t) =?</h3>
T = 2t
3.6 = 2 × t
Divide both side by 2
t = 3.6 / 2
<h3>t = 1.8 s</h3>
<h3>A. Determination of the greatest height.</h3>
Time taken to reach the greatest height (t) = 1.8 s
Acceleration due to gravity (g) = 9.8 m/s²
<h3>Greatest height (h) =?</h3>
h = ½gt²
h = ½ × 9.8 × 1.8²
<h3>h = 15.876 m</h3>
Therefore, the greatest height reached by the ball is 15.876 m
<h3>B. Determination of the initial velocity.</h3>
Greatest height (h) = 15.876 m
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) = 0 (at greatest height)
<h3>Initial velocity (u) =.?</h3>
<h3>v² = u² – 2gh (since the ball is going against gravity)</h3>
0² = u² – (2 × 9.8 × 15.876)
0 = u² – 311.1696
Collect like terms
0 + 311.1696 = u²
311.1696 = u²
Take the square root of both side
u = √311.1696
<h3>u = 17.64 m/s</h3>
Therefore, the ball left the kicker's foot with a speed of 17.64 m/s
Learn more: brainly.com/question/2043600