Answer:
Answered
Explanation:
v= 1 m/s
A= 1 m^2
m= 100 kg
y= 1 mm
μ = ?
ζ= viscosity of SAE 20 crankcase oil of 15° C= 0.3075 N sec/m^2
forces acting on the block are
F_s ← ↓ →F_f
mg
N= mg
F_s= shear force = ζAv/y F_f= friction force = μN
now in x- direction F_s= F_f
ζAv/y = μN
0.3075×1×1×1/1×10^{-3} = μ×100
⇒μ=0.313 (coefficient of sliding friction for the block)
Now, as the velocity is increased shear force also increases and due to this frictional force also increases.
Now, to compensate this frictional force friction coefficient must increase
as v∝μ
Pseudoscience because it involves beliefs not facts
Answer:
Rate of heat transfer will be 10.69 kw
Explanation:
We have given temperature
From standard table enthalpy of vaporization 2382.75 KJ/kg
Steam is coming out from turbine at rate of 16.154 kg/hour
We have to calculate the rate of heat transfer
Heat transfer is equal to
So rate of heat transfer
=
So rate of heat transfer will be 10.69 kw
Answer:
pressure and temperature (assuming volume is constant)
Explanation: