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Semmy [17]
3 years ago
12

A chemical equation is balanced when the

Chemistry
2 answers:
Arada [10]3 years ago
7 0

a balanced chemical equation occurs when the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.

kolezko [41]3 years ago
7 0

Answer:

A balanced chemical equation is balanced when the number of the different atoms of elements in the reactants side is equal to that of the products side. Balancing chemical equations is a process of trial and error.

Explanation:

2 H_{2} + 1 O_{2} = 2 H_{2} O

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A chemistry student needs 50.0 g of methyl acetate for an experiment. By consulting the CRC Handbook of Chemistry and Physics, t
slamgirl [31]

Explanation:

As density is defined as the mass of a substance divided by its volume.

Mathematically,         Density = \frac{mass}{volume}

It is given that mass is 50 g and density is 0.934 g/cm^{3}.

Hence, calculate the volume of methyl acetate as follows.

                     Density = \frac{mass}{volume}

             0.934 g/cm^{3} = \frac{50 g}{volume}

                       Volume = 53.53 cm^{3}

or,                                  = 53.53 ml                (as 1 cm^{3} = 1 mL)

Thus, we can conclude that the volume of methyl acetate the student should pour out is 53.53 ml.

3 0
3 years ago
Concentrated hydrochloric acid, HCl, comes with an approximate molar concentration of 12.1 M. If you are instructed to prepare 3
Semmy [17]

Answer:

28.20 mL of the stock solution.

Explanation:

Data obtained from the question include the following:

Molarity of stock solution (M1) = 12.1 M

Volume of diluted solution (V2) = 350.0 mL

Molarity of diluted solution (M2) = 0.975 M

Volume of stock solution needed (V1) =..?

The volume of stock solution needed can be obtained by using the dilution formula as shown below:

M1V1 = M2V2

12.1 x V1 = 0.975 x 350

Divide both side by 12.1

V1 = (0.975 x 350)/12.1

V1 = 28.20 mL.

Therefore, 28.20 mL of the stock solution will be needed to prepare 350.0 mL of 0.975 M HCl solution.

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3 years ago
34. An electron in the 3d state of the hydrogen atom has a radial part of the wave function of the form A r2 exp(-r/3ao). What i
nikdorinn [45]

Answer: Option (e) is the correct answer.

Explanation:

Formula to calculate radius is as follows.

          p(r) = Ar(r^{2}e^{\frac{-r}{3a_{o}}}

                = Ar^{3}e^{\frac{-r}{3a_{o}}}

     \frac{dp(r)}{dr} = 0

            Ar^{3}e^{\frac{-r}{3a_{o}}}(\frac{-1}{3a_{o}} + Ae^{\frac{-r}{3a_{o}}}(3r^{2}) = 0

                     \frac{Ar^{3}}{3a_{o}}e^{\frac{-r}{3a_{o}}}

                      = 3Ar^{2}e^{\frac{-r}{3a_{o}}}

                       r = 9a_{o}

Thus, we can conclude that most likely radius at which the electron would be found is 9a_{o}.

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Hg-178 undergoes 2 alpha decay and positron emission. Determine the new isotope.
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