The fraction of radioisotope left after 1 day is
, with the half-life expressed in days
Explanation:
The question is incomplete: however, we can still answer as follows.
The mass of a radioactive sample after a time t is given by the equation:
![m(t)=m_0 (\frac{1}{2})^{\frac{t}{\tau}}](https://tex.z-dn.net/?f=m%28t%29%3Dm_0%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B%5Cfrac%7Bt%7D%7B%5Ctau%7D%7D)
where:
is the mass of the radioactive sample at t = 0
is the half-life of the sample
This means that the mass of the sample halves after one half-life.
We can rewrite the equation as
![\frac{m(t)}{m_0}=(\frac{1}{2})^{\frac{t}{\tau}}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%28t%29%7D%7Bm_0%7D%3D%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B%5Cfrac%7Bt%7D%7B%5Ctau%7D%7D)
And the term on the left represents the fraction of the radioisotope left after a certain time t.
Therefore, after t = 1 days, the fraction of radioisotope left in the body is
![\frac{m(1)}{m_0}=(\frac{1}{2})^{\frac{1}{\tau}}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%281%29%7D%7Bm_0%7D%3D%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B%5Ctau%7D%7D)
where the half-life
must be expressed in days in order to match the units.
Learn more about radioactive decay:
brainly.com/question/4207569
brainly.com/question/1695370
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Answer: B
Explanation:the voltage is just like the force that drives the current through out the circui... When trippled, the force increases and the current increases since the resistance in the circuit remains constant.
i think its very hot summers
Answer:
A) continuing search for new knowledge
Explanation:
Science has always been about discovery and gaining knowledge
The definition for nebula is : A cloud of gas and dust in outer space, visible in the night sky either as an indistinct bright patch or as a dark silhouette against other luminous matter.