All categories

2 years ago

The resolution of a camera or other optical system is determined by the relationship between what two scales?

Physics

1 answer:

devlian [24]2 years ago

4 0

Answer:

d.The wavelength of light and the size of the aperture

Explanation:

<em>The resolution power of an optical system is the smallest distance between two points that the device can distinguish clearly.</em>

It has the following relationship:

$r=\frac{\lambda}{2n}$

where:

r = minimum resolvable distance

n = numerical aperture

$\lambda$ = wavelength of the light used for viewing

From above mathematical equation it is clear that:

Smaller the wavelength better the resolving power
Larger the aperture better the resolution

(Note, that smaller the value of "r" the more finer details of the image visible through the device.)

You might be interested in

Which type(s) of electromagnetic radiation do human bodies emit? Which type(s) can our senses detect?

Andrei [34K]

Our bodies emit heat, and nerve endings in our skin can detect it.
Our eyes can detect visible light, but our bodies don't emit that.

6 0

3 years ago

The process by which metamorphic rock changes to igneous rock begins with?

Strike441 [17]

Melting, as igneous rock is magma or lava that has cooled and hardened.

5 0

3 years ago

A car is moving in a straight line with the same speed of 100 m/s ,the acceleration in this

Amiraneli [1.4K]

Answer:

a = 0m/s²

Explanation:

Average acceleration = (change in velocity)/(time it takes). Since the car's change in velocity is zero, its acceleration is zero.

4 0

3 years ago

Find the net work W done on the particle by the external forces during the motion of the particle in terms of the initial and fi

steposvetlana [31]

Answer:

$W=K_f-K_i$

Explanation:

The work done on a particle by external forces is defined as:

$W=\int\limits^{r_f}_{r_i} {F\cdot dr} \,$

According to Newton's second law $F=ma$ . Thus:

$W=\int\limits^{r_f}_{r_i}{ma\cdot dr} \,\\$

Acceleration is defined as the derivative of the speed with respect to time:

$W=m\int\limits^{r_f}_{r_i}{\frac{dv}{dt}\cdot dr} \,\\\\W=m\int\limits^{r_f}_{r_i}{dv \cdot \frac{dr}{dt}} \,$

Speed is defined as the derivative of the position with respect to time:

$W=m\int\limits^{v_f}_{v_i} v \cdot dv \,$

Kinetic energy is defined as $K=\frac{mv^2}{2}$ :

$W=m\frac{v_f^2}{2}-m\frac{v_i^2}{2}\\W=K_f-K_i$

3 0

2 years ago

Why is the contribution of the wavelets lying on the back of secondary wave front zero?

Tresset [83]

Answer:

The contribution of the wavelets lying on the back of the wave front is zero because of something known as the Obliquity Factor. It is assumed that the amplitude of the secondary wavelets is not independent of the direction of propagation, Sources: byju's.com

3 0

1 year ago

Read 2 more answers