All categories

3 years ago

The resolution of a camera or other optical system is determined by the relationship between what two scales?

Physics

1 answer:

devlian [24]3 years ago

4 0

Answer:

d.The wavelength of light and the size of the aperture

Explanation:

<em>The resolution power of an optical system is the smallest distance between two points that the device can distinguish clearly.</em>

It has the following relationship:

$r=\frac{\lambda}{2n}$

where:

r = minimum resolvable distance

n = numerical aperture

$\lambda$ = wavelength of the light used for viewing

From above mathematical equation it is clear that:

Smaller the wavelength better the resolving power
Larger the aperture better the resolution

(Note, that smaller the value of "r" the more finer details of the image visible through the device.)

You might be interested in

If an object is travelling faster than its own sound waves, which of the following is created?

Andrej [43]

Answer:

Explanation:

When an object travels faster than the speed of sound, a sonic boom is created. A ring of pressure waves (probably why wave destruction and pressure cooker are options lol) are created, which is why when you see a jet make a sonic boom there looks like a ring shaped cloud behind it. Hope this helps! For further confirmation/information, just look up sonic boom science (or else you will get sonic boom the video game)

7 0

3 years ago

Read 2 more answers

The position coordinate of a particle which is confined to move along a straight line is given by s =2t3−24t+6, where s is measu

Gre4nikov [31]

Answer:

a) the answer is t=4 seconds

b) acceleration is zero

c) displacement= 142 m

Explanation:

Given the position of the particle

$s=2t^3-24t+6$

a) the time required when velocity $v=72 m/s$

$v=72=\frac{ds}{st}=6t^2-24$

now we solve for time $t$

$6t^2=72+24=96\\\\\implies t^2=\frac{96}{6}\\\therefore t=4 s$

b) acceleration when $v=30 m/s$

acceleration is the time derivative of velocity i.e

$a=\frac{dv}{dt}=\frac{d}{dt}(30)=0$

c) the net displacement of the particle during the interval t = 1 s to t = 4 s is

$s_4-s_1=2t^3-24+6|_{t=4}-2t^3-24+6|_{t=1}\\s_4-s_1=126-(-16)=142 m$

7 0

4 years ago

If a projectile travels in the air for 8 seconds when does a projectile reach its highest point

emmainna [20.7K]

Given

The projectile is in air for a time of t=8 sec

To find

The time it takes to reach the highest point

Explanation

A projectile moves up to the highest point and then again moves down following a parabolic path.

So it will reach the highest point at a time half the time it requires to follow teh parabolic path.

The time taken to reach the highest point is 4 sec

Conclusion

The time taken is 4 sec.

5 0

2 years ago

Wind instruments like trumpets and saxophones work on the same principle as the "tube closed on one end" that we examined in our

Gnom [1K]

Answer:

f = v / 4L

the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.

Explanation:

In wind instruments the wave speed must meet

v = λ f

λ = v / f

from v is the speed of sound that depends on the temperature

v = v₀ $\sqrt{1+ \frac{T [C]}{273} }$

where I saw the speed of sound at 0ºC v₀ = 331 m/s the temperature is in degrees centigrade, we can take the degrees Fahrenheit to centigrade with the relation

(F -32) 5/9 = C

76ºF = 24.4ºC

45ºF = 7.2ºC

With this relationship we can see that the speed of sound is significantly reduced when leaving the house to the outside

at T₁ = 24ºC v₁ = 342.9 m / s

at T₂ = 7ºC v₂ = 339.7 m / s

To satisfy this speed the wavelength of the sound must be reduced, so the resonant frequencies change

λ / 4 = L

λ= 4L

v / f = 4L

f = v / 4L

Therefore, the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.