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3 years ago

The resolution of a camera or other optical system is determined by the relationship between what two scales?

Physics

1 answer:

devlian [24]3 years ago

4 0

Answer:

d.The wavelength of light and the size of the aperture

Explanation:

<em>The resolution power of an optical system is the smallest distance between two points that the device can distinguish clearly.</em>

It has the following relationship:

$r=\frac{\lambda}{2n}$

where:

r = minimum resolvable distance

n = numerical aperture

$\lambda$ = wavelength of the light used for viewing

From above mathematical equation it is clear that:

Smaller the wavelength better the resolving power
Larger the aperture better the resolution

(Note, that smaller the value of "r" the more finer details of the image visible through the device.)

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Romashka [77]

I mean it’s alaska so i’m assuming B but i could be very wrong

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3 years ago

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Substance A has a higher heat capacity than does substance B, and substance B has a higher heat capacity than does substance C.

svetlana [45]

A < B < C

C will increase faster than B which is faster than A

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3 years ago

A capacitor is being charged from a battery and through a resistor of 10 kΩ. It is observed that the voltage on the capacitor ri

swat32

Answer:

$C = 2.48 \times 10^{-4} Farad$

Explanation:

As per the equation of voltage on capacitor we know that

$V = V_{max}(1 - e^{-\frac{t}{\tau}})$

now we know that voltage reached to its 80% of maximum value in 4 second time

so we will have

$0.80 V_{max} = V_{max}(1 - e^{-\frac{4}{\tau}})$

$0.20 = e^{-\frac{4}{\tau}}$

$-\frac{4}{\tau} = ln(0.20)$

$-\frac{4}{\tau} = -1.61$

$\tau = 2.48$

as we know that

$\tau = RC$

$(10 k ohm)(C) = 2.48$

$C = 2.48 \times 10^{-4} Farad$

4 0

3 years ago

Suppose that instead of dropping the rock you throw it downwards so that its speed after falling 7 meters is 23.43 m/s. How much

Shkiper50 [21]

Answer:

3,298.1 Hz

Explanation:

Solution is attached

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3 years ago

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A boat moves through the water with two forces acting on it. One is a 2.05 ✕ 103 N forward push by a motor, and the other is a 1

labwork [276]

Answer:

(a) a= 0.139 m/s²

(b) d= 4.45 m

Explanation:

a) We apply Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass (kg)

a : acceleration (m/s²)

Data

F₁= +2.05 * 10³ N : forward push by a motor

F₂= -1.87* 10³ N : resistive force due to the water.

m= 1300 kg

Calculation of the acceleration of the boat

We replace data in the formula (1):

∑F = m*a

F₁+F₂= m*a

$a=\frac{F_{1} +F_{2} }{m}$

$a= \frac{2.05*10^{3} -1.87*10^{3}}{1300}$

a= 0.139 m/s²

b) Kinematics of the boat

Because the boat moves with uniformly accelerated movement we apply the following formulas:

d= v₀t+ (1/2)*a*t² Formula (2)

vf= v₀+at Formula (3)

Where:

d:displacement in meters (m)

t : time interval (s)

v₀: initial speed (m/s)

vf: final speed (m/s)

a: acceleration (m/s² )

Data

v₀ = 0

a= 0.139 m/s²

t = 8 s

Calculation of the distance traveled by the boat in 8 s

We replace data in the formula (2)

d= v₀t+ (1/2)*a*t²

d= 0+ (1/2)*(0.139)*(8)²

d= 4.45 m

c) Calculation of the speed of the boat in 8 s

We replace data in the formula (3):

vf= v₀+at

vf= 0+( 0.139)*(8)

vf= 1.1 m/s

6 0

4 years ago