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Anna35 [415]
3 years ago
8

In 1940, it was discovered that uranium could be artificially changed to plutonium, a process called transmutation. What combina

tion of decay processes would convert U-239 (92 protons) into Pu-239 (94 protons)?
A. Beta-decay followed by beta decay.
B. Positron emission followed by electron capture.
C. Electron capture followed by alpha decay.
D. Alpha decay followed by beta decay.
Physics
1 answer:
coldgirl [10]3 years ago
4 0

The combination of decay processes that would convert U-239 into PU- 239 is beta decay followed by another beta decay. There are two different types of beta decay (positive and negative beta decays) they both occur simultaneously in order to move the atoms towards stability.

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Question 4 of 20
Mnenie [13.5K]

Answer:

D

Explanation:

F = G m1 m2 / r^2       now double  r

 F =  G m1m1/ (2r)^2

    F =  1/4  G m1m2/r^2     <===== this is 1/4 of the original

5 0
2 years ago
A boy shoves his stuffed toy zebra down a frictionless chute. It starts at a height of 1.69 m above the bottom of the chute with
Veseljchak [2.6K]

Answer:

x = 6.94 m

Explanation:

For this exercise we can find the speed at the bottom of the ramp using energy conservation

Starting point. Higher

            Em₀ = K + U = ½ m v₀² + m g h

Final point. Lower

            Em_{f} = K = ½ m v²

            Em₀ = Em_{f}

            ½ m v₀² + m g h = ½ m v²

            v² = v₀² + 2 g h

             

Let's calculate

             v = √(1.23² + 2 9.8 1.69)

             v = 5.89 m / s

In the horizontal part we can use the relationship between work and the variation of kinetic energy

            W = ΔK

            -fr x = 0- ½ m v²  

               

Newton's second law

              N- W = 0

     

The equation for the friction is

               fr = μ N

               fr = μ m g

We replace

             μ m g x = ½ m v²

             x = v² / 2μ g

Let's calculate

            x = 5.89² / (2 0.255 9.8)

            x = 6.94 m

6 0
4 years ago
Read 2 more answers
At 96° F the saturation density of air is 0.04 kg/m3. If the weather report says the relative humidity is 90 % when the tempera
nalin [4]

Answer:

The value is  H  =  0.036 \ kg/m^3

Explanation:

From the question we are told that

   The saturation density of air is \rho =  0.04 \ kg/m^3

   The temperature for this saturation density to occur  T_s  =  96^o F

    The relative humidity at this temperature is  R_h  =  90\%  =  0.90

Generally the relative humidity is mathematically represented as

      R_H  = \frac{H}{\rho}

Here H represents humidity

=> 0.90 =  \frac{H}{0.04}

=>  H  =  0.90 * 0.04

=>  H  =  0.036 \ kg/m^3

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