The correct answer is the recoil velocity of the cannon is equal to 90m/s.
Answer:
mixture of all colors of ligjt
Answer: The following statement is incorrect: The normal force always points upward (positive y-direction).
Explanation:
The normal force, as his names points out, is always normal to the surface on which the object that is being acted on by this force is placed.
This means that it will always be at straight angles with the surface, regardless of the orientation of the surface.
For instance, in an inclined plane, is directly related with the angle that the plane has with the horizontal, and can be even horizontal if the surface is a vertical wall.
The normal force is one of the components of the contact force (the other one is the fricition force, always parallel to the contact surface), and adopts any needed value to satisfy the Newton's 2nd Law.
a) create an expression
for the ball's initial horizontal velocity, V0x, in terms of the variables
given in the problem statement.
v0x = vf * cos(Θf)
<span>
b) calculate the ball's initial vertical velocity, V0y, in
m/s</span>
v0x = 32.4m/s * cos(-25.5º)
= 29.2 m/s <span>
tanΘ = v1y / v0x → tan(-25.5) = v1y / 29.2m/s → v1y = -13.93
m/s
the vertical velocity when the ball was caught.
(v0y)² = (v1y)² + 2as = (-13.93m/s)² + 2 * 9.8m/s² * 5.5m = 301.78
m²/s²
v0y = 17.37 m/s
c) calculate the magnitude of the ball's initial velocity,
v0, in m/s</span>
v0 = sqrt (v0y^2 +
v0x^2)
v0 = sqrt (17.37^2 + 29.2^2)
m/s
v0 = 33.98 m/s
<span>
d) find the angle, theta0, in degrees above the horizontal at
which which the ball left the bat.</span>
tan Θ = v0y/v0x
<span>Θ = arctan(17.37/29.2) =
30.75º above horizontal</span>
Energy= mass x speed of light squared