Answer:
(a) λ = 4136 nm → infrared
(b) λ = 413.6 nm → visible light
(c) λ = 41.36 nm → ultraviolet
Explanation:
The wavelength of infrared is on the range of 700 nm to 1000000 nm
The wavelength of visible light is between 400 nm and 700 nm
The wavelength of ultraviolet ray on the range of 10 nm to 400 nm
The wavelength of photon is given by;
E = hf
f is the frequency of the wave = c / λ
![E = h\frac{c}{\lambda}\\\\ \lambda = \frac{hc}{E}](https://tex.z-dn.net/?f=E%20%3D%20h%5Cfrac%7Bc%7D%7B%5Clambda%7D%5C%5C%5C%5C%20%5Clambda%20%3D%20%5Cfrac%7Bhc%7D%7BE%7D)
Where;
c is the speed of light = 3 x 10⁸ m/s
h is Planck's constant = 6.626 x 10⁻³⁴ J/s
(a) 0.3 eV = 0.3 x 1.602 x 10⁻¹⁹ J
![\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(0.3)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-6} \ m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B%286.626%20%2A%2010%5E%7B-34%7D%29%283%2A10%5E8%29%7D%7B%280.3%29%2A%281.602%2A10%5E%7B-19%7D%29%7D%5C%5C%5C%5C%5Clambda%20%3D%204.136%20%2A10%5E%7B-6%7D%20%5C%20m)
λ = 4136 x 10⁻⁹ m
λ = 4136 nm → infrared
(b) 3.0 eV
![\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(3)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-7} \ m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B%286.626%20%2A%2010%5E%7B-34%7D%29%283%2A10%5E8%29%7D%7B%283%29%2A%281.602%2A10%5E%7B-19%7D%29%7D%5C%5C%5C%5C%5Clambda%20%3D%204.136%20%2A10%5E%7B-7%7D%20%5C%20m)
λ = 413.6 x 10⁻⁹ m
λ = 413.6 nm →visible light
(c) 30 eV
![\lambda = \frac{(6.626 * 10^{-34})(3*10^8)}{(30)*(1.602*10^{-19})}\\\\\lambda = 4.136 *10^{-8} \ m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20%5Cfrac%7B%286.626%20%2A%2010%5E%7B-34%7D%29%283%2A10%5E8%29%7D%7B%2830%29%2A%281.602%2A10%5E%7B-19%7D%29%7D%5C%5C%5C%5C%5Clambda%20%3D%204.136%20%2A10%5E%7B-8%7D%20%5C%20m)
λ = 41.36 x 10⁻⁹ m
λ = 41.36 nm →ultraviolet
Technically, displacement is the "shortest" distance between any two points. If you say displacement is greater than distance, you will contradict the above statement. Displacement is always less than or equal to distance. Note that distance is a scalar whereas displacement is a vector. :)
We know that the formula for static friction is:
Fs = μ N
where,
μ is the coefficient of static friction = 0.180
N is the normal force = weight of the cup = m g
We also know that from the Newton’s second law of motion,
the formula for net force is:
Fnet = m a
where m is the mass of the cup and a is the acceleration
of the cup
To prevent the cup from sliding backward, the static
friction Fs must cancel out the net Force Fnet, that is:
Fnet – Fs = 0
Therefore:
m a – μ N = 0
m a = μ N
m a = μ (m g)
Cancelling m:
a = μ g
a = 0.180 (9.81 m / s^2)
a = 1.7658 m / s^2
Therefore the plane can only have an acceleration of
about 1.77 m/s^2 before the cup starts to slide.
Answer:
the answer might the number 2
Explanation: