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3 years ago

What’s the answer for this

Physics

2 answers:

AlladinOne [14]3 years ago

8 0

Answer:

52.5 m

Explanation:

The displacement is the area under the velocity vs time graph.

From 0 to 5 seconds, the area is the area of the triangle plus the area of the rectangle.

x = ½ (3 s) (15 m/s) + (2 s) (15 m/s)

x = 52.5 m

MA_775_DIABLO [31]3 years ago

3 0

52.5

Glad I could help you

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Answer:

vf₂ = 15.79 m/s

Explanation:

Theory of collisions

Linear momentum is a vector magnitude (same direction of the velocity) and its magnitude is calculated like this:

p=m*v

where

p:Linear momentum

m: mass

v:velocity

There are 3 cases of collisions : elastic, inelastic and plastic.

For the three cases the total linear momentum quantity is conserved:

P₀ = Pf Formula (1)

P₀ :Initial linear momentum quantity

Pf : Final linear momentum quantity

Data

m₁ = 2600 kg : mass of the rhino

m₂= 0.18 kg : mass of the ball

v₀₁ = 3.70 m/s : initial velocity of the rhino

v₀₂= - 8.39 m/s, initial velocity of the ball

Problem development

We appy the formula (1):

P₀ = Pf

m₁*v₀₁ + m₂*v₀₂ = m₁*vf₁ + m₂*vf₂

(2600)*(3.7) + (0.18)*(- 8.39) = (2600)*vf₁ +(0.18)*vf₂

9620 -1.5102 = (2600)*vf₁ +(0.18)*vf₂

9618.4898 = (2600)*vf₁ +(0.18)*vf₂ Equation (1)

Because the shock is elastic, the coefficient of elastic restitution (e) is equal to 1.

$e = \frac{v_{f2}-v_{f1} }{v_{o1}-v_{o2}}$

1*( v₀₁- v₀₂ ) = (vf₂ -vf₁)

( 3.7 -( -8.39 ) = (vf₂ -vf₁)

12.09 = (vf₂ -vf₁)

vf₂ = vf₁ + 12.09 Equation (2)

We replace Equation (2) in the Equation (1)

9618.4898 = (2600)*vf₁ +(0.18)*vf₂

9618.4898 = (2600)*vf₁ +(0.18)* (vf₁ + 12.09)

9618.4898 = (2600)*vf₁ +(0.18)*vf₁ + (0.18)(12.09)

9618.4898 = (2600)*vf₁ +(0.18)*vf₁ + 2.1762

9618.4898 -2.1762 = (2600.18)*vf₁

9616.3136 = (2600.18)*vf₁

vf₁ = (9616.3136) / (2600.18)

vf₁ = 3.698 m/s : Final velocity of the rhino

We replace vf₁ = 3.698 m/s in the Equation (2)

vf₂ = vf₁ + 12.09

vf₂ = 3.698 + 12.09

vf₂ = 15.79 m/s : Final velocity of the ball

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3 years ago

In Fig., block 1 of mass m1 slides from rest along a frictionless ramp from height h = 2.50 m and then collides with stationary

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Answer:

Explanation:

Given

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$v_2=\frac{0+2m_1\times 7}{m_1+2m_1}$

$v_2=\frac{14}{3} m/s$

using $v^2-u^2=2 as$

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$s=2.22\ m$

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In Completely Inelastic objects stick with each other

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$v=\frac{u_1}{3}=\frac{7}{3} m/s$

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Answer:

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m₁ u₁ + m₂ u₂ = m₁ v + m₂ v

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