Explanation:
Water (H2O) as a polar covalent molecule has its arrangement of oxygen and hydrogen atoms where one end (hydrogen) has a partially positive charge while the other side (oxygen) had a partially negative charge.
It is also capable of forming hydrogen bonds with polar molecules. Each water molecule can form two hydrogen bonds involving their hydrogen atoms and two further hydrogen bonds using the hydrogen atoms attached to neighboring water molecules.
A convex mirror has a radius of curvature of 30 cm. an object is placed at a distance of 30 cm in front of the mirror. compute the location of the shadows and shadow enlargement!
Answer:
31.8 × 10⁻⁴ J = 3.18 mJ
Explanation:
We know the intensity I of a wave is I = P/A where P = power and A = area = 0.500 m²
The intensity of an electromagnetic wave is also equal to I = E₀²/μ₀c
where E₀ = maximum electric field strength = √2E where E = rms value of electric field = 0.0200 N/C, μ₀ = 4π × 10⁻⁷ H/m ,c = 3 × 10⁸ m/s
P/A = E₀²/μ₀c = 2E²/μ₀c
P = 2E²A/μ₀c = 2 × (0.02 N/C)² × 0.5 m²/(4π × 10⁻⁷ H/m × 3 × 10⁸ m/s)
= 1.06 × 10⁻⁴ W = 0.106 mW
Since P = E/t where E = Energy and t = time
E = Pt with t = 30 s
E = 1.06 × 10⁻⁴ W × 30 s = 31.8 × 10⁻⁴ J = 3.18 mJ
So the wave carries 3.18 mJ of energy through the window in 30 s
Answer:
The answer is 34.119m
Explanation:
You need to pay attention to the word "uniformly". It means there is no acceleration thus the physics of this problem respond to the uniform rectilinear motion equations:
- Xf = Xo + vt
- v = constant
- a = 0
where:
- v = velocity (speed)
- t = time
- a = acceleration
Xf = 0 + (15.3)(2.23)
Xf = 34.119m
Answer:
2.3687599 m/s
0.91106 m/s
0.617213012 J
Explanation:
f = Frequency = 
A = Amplitude = 0.13 m
k = Spring constant
m = Mass of object = 0.22 kg
Angular velocity is given by

Velocity is given by

Speed when it passes the equilibrium point is 2.3687599 m/s
Frequency is given by

x = Displacement = 0.12 m
In this system the energies are conserved

The speed when it is 0.12 m from equilibrium is 0.91106 m/s
The energy in the system is given by

The total energy of the system is 0.617213012 J