Question

Who knows how about to do this??

Answer 1

Answer:

$f(4) = 2$

Step-by-step explanation:

1. $f(n)=5n+8$

$f(4)=\\\\f(-2)$

Replace $n$ with $4$; solve

$f(n)=5n+8\\\\f(n)=5(4)+8\\\\5(4)\\\\20+8\\\\28$

Therefore, $f(4) = 28$

Replace $n$ with $-2$

$f(n)=5n+8\\\\f(n)=5(-2)+8\\\\5(-2)\\\\-10+8\\\\-2$

Therefore, $f(-2) = -2$

2.  $f(n)=-2n+1$

$f(10)=\\\\f(-1)=$

Replace n with 10; solve

$f(n)=-2n+1\\\\f(n)=-2(10)+1\\\\-2(10)\\\\-20+1\\\\-19$