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anygoal [31]
3 years ago
6

HELP ASAP!! THIS IS DUE TOMORROW!! I WILL MARK YOU AS A BRAINLIEST IF ANSWERED NOW!! #1-7

Chemistry
1 answer:
gayaneshka [121]3 years ago
7 0
O two gained
Fe three lost
Br one gained
Ni two lost
K one lost
F one gained
P three gained
-=gained as electrons have a negative charge
+=lost electrons
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What is the basic definition of carbohydrates
ikadub [295]

Carbohydrates are substances that are found in foods such as bread and pasta, which provide the body with heat and energy. Chemically, carbohydrates are made of three kinds of elements namely carbon , hydrogen and oxygen.

Carbohydrates are separated into two main categories, simple carbohydrates and complex carbohydrates.  

Simple carbohydrates are those that contain one or two sugar molecules linked together. Complex carbohydrates are those that contain  three or more sugar molecules linked together. In some cases these chains can contain hundreds of sugar molecules. 

 

8 0
3 years ago
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What is water's density at 93 ∘C? Assume a constant coefficient of volume expansion. Express your answer with the appropriate un
Ganezh [65]

Answer:

982.5 kg/m³

Explanation:

When the temperature of a fluid increases, it dilates, and because of the variation of the volume, it's density will vary too. The density can be calculated by the expression:

ρ₁ = ρ₀/(1 + β*(t₁ - t₀))

Where ρ₁ is the final density, ρ₀ the initial density, β is the constant coefficient of volume expansion, t₁ the final temperature, and t₀ the initial temperature.

At t₀ = 4°C, the water desity is ρ₀ = 1,000 kg/m³. The value of the constant for water is β = 0.0002 m³/m³ °C, so, for t₁ = 93°C

ρ₁ = 1,000/(1 + 0.0002*(93 - 4))

ρ₁ = 1,000/(1+ 0.0178)

ρ₁ = 982.5 kg/m³

3 0
3 years ago
If the starting volume of a hot air balloon is 55,500 m3and the initial temperature is 21 °C, what is the temperature inside the
Dmitry_Shevchenko [17]

Answer:

T₂ = 392 K

Explanation:

Given that,

Initial volume of the hot air balloon, V₁ = 55500 m³

Initial temperature, T₁ = 21°C = 294 K

Final volume, V₂ = 74000 m³

We need to find the final temperature inside the balloon. The relation between the temperature and volume is given by charles law i.e.

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Where

T₂ is the final temperature

So,

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\T_2=\dfrac{T_1V_2}{V_1}\\\\T_2=\dfrac{294\times 74000 }{55500 }\\\\T_2=392\ K

So, the new temperature is 392 K.

8 0
2 years ago
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Lostsunrise [7]

Uhhhhhhhhhhhhhh wut, can you rewrite it?

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3 years ago
Use the given figure to complete the statement below.
MakcuM [25]

Easy, its vertical :3


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